My achilles heel....

- anonymous

My achilles heel....

- Stacey Warren - Expert brainly.com

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- chestercat

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- anonymous

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- anonymous

These types of integrals have always been hard, Id appreciate any step by step explanation :)

- IrishBoy123

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## More answers

- IrishBoy123

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- UsukiDoll

ah long division. because the exponent in the denominator is higher than the one int he numerator.

- anonymous

Usuki!! :)

- UsukiDoll

do you know long division?

- anonymous

kind of, I think I do.

- UsukiDoll

I have faith in you . you can do it ;)

- imqwerty

^ :D

- anonymous

Im afraid faith cant save u or me...help:)?

- UsukiDoll

@imqwerty is a good helper. He will guide you ! :D

- anonymous

bhaiya help?

- imqwerty

â€¢_â€¢)

- anonymous

haha dont we all have to do that :)

- anonymous

Back to my problem yaar...I got the last exam in calc 2 ever given in sweden, no chance to fail this.

- anonymous

Guys....my problem?

- IrishBoy123

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- IrishBoy123

finish it off now?

- UsukiDoll

don't we have to switch signs for polynomial long division though?

- imqwerty

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- UsukiDoll

how the....... O_O @imqwerty what did you do?

- imqwerty

:D

- anonymous

Guys those methods u showed I dont know them....

- imqwerty

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- nincompoop

he used factorization to break the denominator

- UsukiDoll

what! everyone should know long division by now.
as for those separate integrals.. I see log and arctan

- UsukiDoll

I know that we can use factorization on the denominator to get x (x^2+1) . I'm talking about the numerator part. @imqwerty got it uber fast.

- anonymous

alright go on imqwerty.

- UsukiDoll

I'm 94 SS NOW! XD!

- nincompoop

that is not how you properly break the sum of terms with denominator although they yield the same quotient

- imqwerty

i broke the equation into 2 parts nd spiltted them nd now we get a cute thing which can be solved easily :)

- UsukiDoll

. We know that the exponent in the denominator is huge than the one in the numerator so we need to use long division to fix this problem

- anonymous

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- anonymous

but @imqwerty what happened to 2x^2+x+2?

- UsukiDoll

that's what I'm wondering too... for the numerator.

- imqwerty

did u get how i broke the equation??

- UsukiDoll

I got the steps after the equation got broken up

- anonymous

could u break the equation, thats the only unclear part. otherwise it was very fast and welldone.

- nincompoop

I get how you did it but we do not know how the terms are properly constructed to yield the sum of terms I do not think that is mathematically sound:
\(\large \frac{2x^2}{x^3+x}+\frac{x}{x^3+x}+\frac{2}{x^3+x} \rightarrow \frac{2x^3}{x(x^2+1)}...\)

- IrishBoy123

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- imqwerty

try takin LCM of those those to terms nd u'll see the original equation appears
ok in such questions in which both the numerator and denominator have x our strategy shuld be to break the equation into parts so that all the x terms vanish frm the numerator

- IrishBoy123

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- imqwerty

now what i did = (2x^2 + x +2)/(x^3 + x)
=2/x + 1/(x^2+1)
if u solve this^ then we get ------> [2(x^2+1) + x]/[x(x^2+1)]
=(2x^2 + x+2)/(x^3+x)
we did nothin wrng we jst altered the equation so as to make it easy to differentiate :)

- nincompoop

clever I must say

- imqwerty

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- imqwerty

:D

- IrishBoy123

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- imqwerty

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- IrishBoy123

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- anonymous

thnx, this wasnt easy I must say.

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