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anonymous
 one year ago
where do I go wrong...
anonymous
 one year ago
where do I go wrong...

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439117048654:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439117111328:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the answer should be cos6t/12+c

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2both answers are correct

hartnn
 one year ago
Best ResponseYou've already chosen the best response.3your approach and answer is correct, you just got an equivalent answer! try to resubstitute u by sin 3t

hartnn
 one year ago
Best ResponseYou've already chosen the best response.3and then apply the double angle formula for cos 2x if you need the answer in terms of cos 6x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0in that case, finally! :D

hartnn
 one year ago
Best ResponseYou've already chosen the best response.3you got it ? you'd get sin^2 3t and would use \(\cos 2x= 12\sin^2 x\) formula....

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2I don't see anything wrong with it either. the usub is correct u = sin3t du = cos3t(3) dx 1/3 du = cos3t dx

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2you could also try dw:1439117565392:dw

hartnn
 one year ago
Best ResponseYou've already chosen the best response.3was just about to tell that^^ :P

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2then for double angle formula... notice that our original problem has a 3? \[\cos 2x= 12\sin^2 x \] this is just standard... but by mutliplying 3 \[\cos 2(3)x= 12\sin^2 3x \] \[\cos 6x= 12\sin^2 3x \]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2multiply 3 on the left side for cos2(3) x ... but the 3 is needed to fit your question on the right hand side.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2remember, indefinite integral gives you a whole family of functions which are unique only upto a constant \(\cos 6x = 12\sin^23x\) so, \(\cos 6x \equiv 2\sin^23x\pmod{\text{constant functions}}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Really good tips guys, thank you all :)
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