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rvc
 one year ago
Please Help.
I need help with the first two questions.
And is the third answer's solution's step is correct?
rvc
 one year ago
Please Help. I need help with the first two questions. And is the third answer's solution's step is correct?

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hartnn
 one year ago
Best ResponseYou've already chosen the best response.2know the a^3 b^3 formula?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2use the property that, in a quadratic equation ax^2+bx+c=0 sum of roots = b/a product of roots = c/a find the difference of roots from the above two values

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2difference^2 = sum^2 4*product

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The third one looks correct. So the solutions would be the appropriate roots of unity. For the second one , write \(x_n\) as \(e^{i\frac{\pi}{2^n}}\) and proceed.

rvc
 one year ago
Best ResponseYou've already chosen the best response.1hmmm.. i gtg now too busy atm ill check these sums later. Thanks to all. If i require help i will surely tag u ppl. :) thanks once again

rvc
 one year ago
Best ResponseYou've already chosen the best response.1second question? how to do?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Like I said, note that \(x_n = e^{i\frac{\pi}{2^{n}}}\) Now multiply the \(x_n\)'s and you will notice an infinite sum in the exponent. Tell me when you get that far.

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1please, note that, in the first question, we have not a quadratic equation @hartnn

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1@nincompoop please help

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1@dan815 please help

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1@phi please help

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1@Loser66 @Hero please help

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1@mukushla please help

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1what do you think about the first question? @Hero

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sry Michele what's the problem?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1if please can help us to solve the first question @mukushla

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@rvc please recheck the problem 1, it seems incorrect!

dan815
 one year ago
Best ResponseYou've already chosen the best response.0try just plugging in a and b and get expressions for a and b

dan815
 one year ago
Best ResponseYou've already chosen the best response.0\[a^26\sqrt{a}+4=0\\ b^26\sqrt{b}+4=0\]

dan815
 one year ago
Best ResponseYou've already chosen the best response.0not sure where to take it from here u can get some expressions for a^3b^3

dan815
 one year ago
Best ResponseYou've already chosen the best response.0\[a^3=(4+6\sqrt{a})^{3/2}\\ b^3=(4+6\sqrt{b})^{3/2}\] or \[(\frac{(a^2+4)}{6})^6=a^3 \\ (\frac{(b^2+4)}{6})^6=b^3\]

dan815
 one year ago
Best ResponseYou've already chosen the best response.0oh i checked ur solution on wolfram i think your question is wrong, because http://www.wolframalpha.com/input/?i=x^26*sqrt%28x%29%2B4%3D0 that equation as real roots

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1thanks! for your replies @dan815
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