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Astrophysics
 one year ago
What is the most interesting math problem you've encountered that you could share? Post away!
Astrophysics
 one year ago
What is the most interesting math problem you've encountered that you could share? Post away!

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amilapsn
 one year ago
Best ResponseYou've already chosen the best response.0Do you know how to prove all triangles are isosceles?

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.0 the sum of two opposite sides and a diagonal of a quadrilateral is 20cm. The area of quadrilateral is 50cm^2. Find the length of the other diagonal. this question is 100% correct and no information is missing :) :D

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.9Haha, that sounds surprisingly easy, but it's not..hmm

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1My all time favorite math problem is a proof: The quadratic reciprocity law. For distinct odd primes \(p,q\), show that \[\large (p/q)(q/p)=(1)^{\frac{p1}{2}\frac{q1}{2}}\] (Gauss got so much obsessed with this problem and called it law ) https://en.wikipedia.org/wiki/Quadratic_reciprocity

thomas5267
 one year ago
Best ResponseYou've already chosen the best response.0@imqwerty Does the quadrilateral has to be convex?

thomas5267
 one year ago
Best ResponseYou've already chosen the best response.0Would this be a valid quadrilateral under the scope of that question? dw:1439136713982:dw

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.0its not given in the question so u can take any quadrilateral.

thomas5267
 one year ago
Best ResponseYou've already chosen the best response.0"the sum of two opposite sides and a diagonal of a quadrilateral is 20cm." Which of the following is true? one side + opposite side + diagonal = 20 cm; or, one side + opposite side = diagonal = 20 cm

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0recently reasoning questions are fascinating

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.0does it work with other integer or Z+ values?

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.0the boxes for astro

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.0nevermind, I just checked it myself

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1@mukushla is the answer emptyset ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1the given equation can be rearranged as a^3  b^3 = 199*200*ab (ab)(a^2+ab+b^2)=199*200*ab (ab)(a/b+b/a+1) = 199*200 since the right hand side is integer, it must be the case that a/b+b/a is also an integer only integer value of a/b+b/a is 2 and this doesn't satisfy the equation, so there are no solutions

ikram002p
 one year ago
Best ResponseYou've already chosen the best response.0you might sound this crazy but my favorite is (The Alternate Angle Theorem ) Proof xD

ikram002p
 one year ago
Best ResponseYou've already chosen the best response.0my second lovely problem is an OS question :3 http://openstudy.com/study#/updates/53ee042fe4b0f30a87d63d4d http://openstudy.com/study#/updates/53ecad4be4b01789aba50084 http://openstudy.com/study#/updates/53ef2279e4b01789aba66331

ikram002p
 one year ago
Best ResponseYou've already chosen the best response.0i also liked 1+1 which Bertrand Russell stated in logic , i dont think that ur post wide enough to handle the rest of mine so i'll stay and see what others lovely problems that users have. thanks @Astrophysics :3

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1abbot and costello: 7x13=28 https://www.youtube.com/watch?v=xkbQDEXJy2k

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.9Haha that was good amistre, thanks xD This is turning out pretty nice, thanks everyone for sharing! Nice posts @ikram002p hehe, I also enjoyed this post ganeshie made for a triple integral a while back http://openstudy.com/users/ganeshie8#/updates/54de8a16e4b0b0ad8854cba3

ali2x2
 one year ago
Best ResponseYou've already chosen the best response.0The most interesting I've found is 2+2 :) Its 22 :D

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1Cantors argument that the real numbers are uncountable. It suffices to show that \((0,1)\) is uncountable. Suppose it was, then we can make a list as follows \(0.a_1a_2a_3a_4...\) \(0.b_1b_2b_3b_4...\) \(0.c_1c_2c_3c_4...\) \(0.d_1d_2d_3d_4...\) \(0.e_1e_2e_3e_4...\) \(0.f_1f_2f_3f_4...\) . . . Consider the number \(0.abcdef\) where \(a=1\) if \(a_1\ne a\) else \(a=0\) and \(b=1\) if \(b_2\ne b\) else \(b=0\) and \(c=1\) if \(c_3\ne c\) else \(c=0\). It is not on the list!

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1There are little things I left out, but that is pretty much the thing :)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.9Ahh yes, I've heard of this, thank you so much for bringing this up, this is great!

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1dw:1439174881229:dw Area of entire square \((a+b)^2\) Area of entire square broken into chunks \(4*\frac{2}{1}a*b+c^2\) set them equal \(4*\frac{1}{2}a*b+c^2=(a+b)^2\\\cancel{2ab}+c^2=a^2+\cancel{2ab}+b^2\) \[a^2+b^2=c^2\]

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1My drawing could be better lol :)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.9Nice one, and don't worry about it haha

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1That cantor argument should also say \(a=1\) if \(a_1\ne 1\) else \(a=0\) \(b=1\) if \(b_2\ne 1\) else \(b=0\) . . .

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What about you,@Empty ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do people encounter their own problem?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1ohh right, that is a blunder lol

ikram002p
 one year ago
Best ResponseYou've already chosen the best response.0lets try to solve it in separate question :)

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0One I missed on the Putnam, many years ago. 1) Given a rectangle with the center identified. 2) Shoot an infinitely elastic point in any direction. 3) Bounce off the infinitely elastic walls if necessary  and it usually will be. 4) The point escapes the rectangle ONLY at the corners. 5) What is the expected number of bounces for the point to exit? Obviously, there are 4 directions with 0 bounces. Obviously, there are 8 directions with 1 bounce. Now what?

Jack1
 one year ago
Best ResponseYou've already chosen the best response.0a girl on here asked me to calculate how much wood a woodchuck could chuck once... she was pretty so i tried...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(9^62773 + 2)^83721 (9 to the 62773 power plus 2) to the 83721 power. It caught my eye
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