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mathmath333
 one year ago
Reasoning question
mathmath333
 one year ago
Reasoning question

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mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0\(\large \color{black}{\begin{align} & \normalsize \text{Find the odd man out}\hspace{.33em}\\~\\ & a.)\ 324 \hspace{.33em}\\~\\ & b.)\ 244 \hspace{.33em}\\~\\ & c.)\ 514 \hspace{.33em}\\~\\ & d.)\ 136 \hspace{.33em}\\~\\ \end{align}}\)

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0\(324=2^{2}\times 3^{4}\\ 224=2^{2}\times 61\\ 514=2^{3}\times 257\\ 136=2^{3}\times 3^{4}\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0Hint : sum of digits

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0sum of digits \(324\rightarrow 9\\ 224\rightarrow 8\\ 514\rightarrow 10\\ 136\rightarrow 10\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Using sum of digits, a) is the odd man out. Also, d) is odd man out considering the one's digit.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@mathmath333 , there's something wrong with your prime factorizations. And the second number is 244, not 224.

amilapsn
 one year ago
Best ResponseYou've already chosen the best response.1b) too @ospreytriple because its first digit isn't odd!

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0this one \(324=2^{2}\times 3^{4}\\ 244=2^{2}\times 61\\ 514=2\times 257\\ 136=2^{3}\times 3^{4}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@mathmath333 , \(136 = 2^3 \times 17\)

thomas5267
 one year ago
Best ResponseYou've already chosen the best response.0It could be argued that 514 is the odd one as its prime factorisation contains only two primes. Or even the answer is none of above as all of the options are numbers not man.
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