## purplemexican one year ago im getting x=-6 is that correct? @Nnesha @madhu.mukherjee.946 @mathstudent55

1. Purplemexican

2. Nnesha

how did you get -6 ?

3. Purplemexican

im not entirely sure im still half asleep

4. Nnesha

show ur work. same like the last one 1st) take square both sides

5. Nnesha

$\huge\rm ( \sqrt{-3x-2})^2=(x+2)^2$ when you take square on left side square root would cancel out $\huge\rm -3x-2=(x+2)^2$ now solve for x (x+2)^2 is same as (x+2)(x+2) apply the foil method

6. Purplemexican

$-3x -2=(x+2)^2$

7. Purplemexican

x=-6, -1

8. Nnesha

hmm

9. Purplemexican

-1 works as a solution and so does -6 how am i still getting these

10. Nnesha

yes so answer is what ?

11. Purplemexican

i don't know I'm so confused right now

12. Nnesha

$$\color{blue}{\text{Originally Posted by}}$$ @purplemexican -1 works as a solution and so does -6 how am i still getting these $$\color{blue}{\text{End of Quote}}$$ okay substitute x for -6

13. Nnesha

$\sqrt{-3(-6)-2}=-6x+2$ both sides are e qual ?

14. Purplemexican

thats where i messed up

15. Purplemexican

i did -3(-6)-2=(-6+2)^2

16. Nnesha

no don't take square root on right side

17. Nnesha

we need to plug in -6 into the original equation :=)

18. Nnesha

$$\color{blue}{\text{Originally Posted by}}$$ @Nnesha $\sqrt{-3(-6)-2}=-6x+2$ both sides are e qual ? $$\color{blue}{\text{End of Quote}}$$ correction $\sqrt{-3(-6)-2}=-6+2$ both sides are e qual ?

19. Nnesha

1sT) multiply -3 times -6 2nd) subtract -2 take square root of that number

20. Purplemexican

4

21. Nnesha

okay so 4=-6+2 both sides are equal ?

22. Purplemexican

no

23. Nnesha

so that's an extraneous solution

24. Purplemexican

thank you again

25. Nnesha

my pleasure. good job!