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anonymous

  • one year ago

A rectangle & a equilateral triangle each have at least one side that is 6 inches long. Their permiters are equal. How do I find the area ?

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  1. anonymous
    • one year ago
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    @Nnesha can u help me again ?

  2. zepdrix
    • one year ago
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    |dw:1439135991231:dw|

  3. zepdrix
    • one year ago
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    Each has a side that is 6 inches long. Since the triangle is equilateral, that tells us that all sides are 6.

  4. zepdrix
    • one year ago
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    We'll label the width or the length of the rectangle as 6, but not both. It doesn't matter which.

  5. zepdrix
    • one year ago
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    |dw:1439136111337:dw|

  6. zepdrix
    • one year ago
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    Let's calculate the perimeter of each shape.\[\large\rm \color{royalblue}{P_{\square}=6+w+6+w}\]\[\large\rm \color{green}{P_{\triangle}=6+6+6}\]They tell us that the perimeters are equal:\[\large\rm \color{royalblue}{P_{\square}}=\color{green}{P_{\triangle}}\]\[\large\rm \color{royalblue}{6+w+6+w}=\color{green}{6+6+6}\]

  7. zepdrix
    • one year ago
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    Solve this equation for w, the width. You already have your length, so after you find your width, the area of your rectangle will given simply by length times width.

  8. anonymous
    • one year ago
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    @zepdrix what's the equation ?

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