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anonymous

  • one year ago

what is the focus of the parabola given by -1/4(y+2)^2=(x-1)

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  1. hartnn
    • one year ago
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    focus of parabola with the equation \((y+h)^2 = a(x-b)+k \) is \((a+h,k)\) now compare your equation with this standard equation and find a,h,k

  2. anonymous
    • one year ago
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    there is no a or k in this equation

  3. hartnn
    • one year ago
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    we need to compare equations! first multiply both sides by -4

  4. hartnn
    • one year ago
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    |dw:1439137783807:dw|

  5. anonymous
    • one year ago
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    I don't get it

  6. hartnn
    • one year ago
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    |dw:1439138094438:dw|

  7. anonymous
    • one year ago
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    (4+2,0)

  8. anonymous
    • one year ago
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    so (6,0)?

  9. hartnn
    • one year ago
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    h= +2, a =-4

  10. anonymous
    • one year ago
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    that isn't one of my options

  11. hartnn
    • one year ago
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    h+a = 2-4 = -2 (-2, 0) is not in the options?

  12. anonymous
    • one year ago
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    well kind of, it's in reverse though, (0,-2)

  13. anonymous
    • one year ago
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    Does it make a difference?

  14. hartnn
    • one year ago
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    then i might have my formula wrong.. (k, a+h) but yes, the focus is indeed (0,-2) verified from : http://www.wolframalpha.com/input/?i=focus+of+-1%2F4%28y%2B2%29%5E2%3D%28x-1%29+

  15. anonymous
    • one year ago
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    okay thank you for your help

  16. hartnn
    • one year ago
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    welcome ^_^

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