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anonymous
 one year ago
what is the focus of the parabola given by 1/4(y+2)^2=(x1)
anonymous
 one year ago
what is the focus of the parabola given by 1/4(y+2)^2=(x1)

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hartnn
 one year ago
Best ResponseYou've already chosen the best response.1focus of parabola with the equation \((y+h)^2 = a(xb)+k \) is \((a+h,k)\) now compare your equation with this standard equation and find a,h,k

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0there is no a or k in this equation

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1we need to compare equations! first multiply both sides by 4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that isn't one of my options

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1h+a = 24 = 2 (2, 0) is not in the options?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well kind of, it's in reverse though, (0,2)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Does it make a difference?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1then i might have my formula wrong.. (k, a+h) but yes, the focus is indeed (0,2) verified from : http://www.wolframalpha.com/input/?i=focus+of+1%2F4%28y%2B2%29%5E2%3D%28x1%29+

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay thank you for your help
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