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anonymous
 one year ago
Which of the following logarithmic equations has no solution?
log4(x + 2) = log4(6  x)
log4(x) = 1
log4(x + 2) = 1
log4(x+2) = log4(x+6)
anonymous
 one year ago
Which of the following logarithmic equations has no solution? log4(x + 2) = log4(6  x) log4(x) = 1 log4(x + 2) = 1 log4(x+2) = log4(x+6)

This Question is Closed

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0try to solve for x hint:hint: \[\huge\rm log_b a=\log_b c\] \[\large\rm \cancel{log_b} a=\cancel{\log_b }c\] a=c

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0bases of the log are same both sides so you cancel out log_B

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh so it would just be x+2=6x

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0also try finding the log of 4 on your calculator

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0 or the log of any negative for that matter

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0for 2nd) 3rd) you need to convert log to exponential form dw:1439137679880:dw after that you can plugin the x value to check ur answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0non real answer, so that means it would be log4(x) = 1 , right?

jhonyy9
 one year ago
Best ResponseYou've already chosen the best response.0so like a first step i think you need to know where is deffined the logaritmic function ? ok ?

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0oh second thoughts x could be negative  in which case x is positive  so its not the second option

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\(\color{blue}{\text{Originally Posted by}}\) @arnavmishra oh so it would just be x+2=6x \(\color{blue}{\text{End of Quote}}\) yes right but you can solve for x there is a solution.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i ended up with log4(x + 2) = 1, is that the right answer?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0well solve that for x x= ??

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0for example first one \[x+2=6x\] solve for x move the x to the left side and 2 to the right side \[x+x=62\]\[2x=4\] x=2 now plugin the 2 into the original equation for x \[\log_4(2+2)=\log_4(62)\] both sides are equal so 2 is a solution

phi
 one year ago
Best ResponseYou've already chosen the best response.0the last choice \[ \log_4(x+2) = \log_4(x+6) \] make each side the exponent of the base 4: \[ 4^{\log_4(x+2) }= 4^{\log_4(x+6)}\\ x+2= x+6 \] (we could have "jumped" to this equation) now add x to both sides: \[xx+2 = xx + 6\\ 2= 6\] we know 2 is not 6, so something is wrong... namely there is no solution to the original expression.
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