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vera_ewing

  • one year ago

chem question

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  1. Rushwr
    • one year ago
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    did use this equation? \[\Delta G = -RTK _{eq}\]

  2. Rushwr
    • one year ago
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    how did u get that?

  3. Rushwr
    • one year ago
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    show me ur work

  4. Rushwr
    • one year ago
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    @Photon336

  5. Photon336
    • one year ago
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    ah yes

  6. Photon336
    • one year ago
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    you need to use \[\Delta G = -RTlnKc\]

  7. Photon336
    • one year ago
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    Kc = 54.8 450 C + 273 = 723 K R = 0.008314 Kj/K*mol plug these all in but let me double check the units first.

  8. Photon336
    • one year ago
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    Vera_ewing let me check this first

  9. Photon336
    • one year ago
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    we know that our Kc > 1 so our delta G must be negative from our equation. I think it's -24.1 kj/mol

  10. Photon336
    • one year ago
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    \[-(723K)(0.008314Kj/mol)Ln(54.3) \]

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