Create a rational function with a linear binomial in both the numerator and denominator.
Part 1. Graph your function using technology. Include the horizontal and vertical asymptotes and the x- and y-intercepts on your graph. Label the asymptotes and intercepts.
Part 2. Show all work to identify the vertical asymptote, the x-intercepts, and the y-intercept.

- help_people

- schrodinger

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- help_people

- help_people

- welshfella

ax + b
------
cx - d
plug in values for a b c and d ( not = 0)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- help_people

a=1 b=2 c=3 d4? is that good? @welshfella srry i was inactive :(

- welshfella

yes so we have
x + 2
-----
3x + 4
you can use desmos to graph this

- welshfella

https://www.desmos.com/calculator/5qfhpf8bgt
asymptotes are breaks in the graph

- welshfella

you see that the x intercept is at (-2,0)

- help_people

ok

- welshfella

what is the y-intercept

- help_people

0.5

- help_people

x= -2

- welshfella

y = 0.5
they want the coordinates of the point which is x = 0 y = 0.5 or (0,0.5)

- help_people

ok

- welshfella

y intercept is at ( 0 , 0.5)

- help_people

ok

- welshfella

now the vertical asymptote is the line between where the vertical parts of the go 'off the page'

- welshfella

thats between x = -1 and x = -2 and its difficult to get from the graph
vertical asymptotes occur when the denominator is zero so we can work it ouT:-
3x + 4 = 0
3x = -4
x = -4/3 or about -1.33

- help_people

should i put x-intercept also ?

- welshfella

yea we 've done that

- welshfella

to work it out we put (x + 2) / (3x + 4) = 0
so x+ 2 = o and x = -2
x intercept at (-2 , 0)

- help_people

how would you work out the intercept

- help_people

*y-intercept

- welshfella

put x = 0 in ( x +2) / (3x + 4)

- welshfella

because at the intercepts x = 0

- help_people

so (0+2) /3(0) + 4)?
(2)/ (0+4)
2/4
1/2?

- welshfella

yes - which is what we read off on the graph

- help_people

and also the vertic asymptotes is -4/3 OR about -1.33 right but what about the horizontal ?

- welshfella

i cant remember !! lol
hold on

- help_people

and ok :)

- help_people

srry I'm throwing everything @ you!

- welshfella

i gotta go right now
as you see form the graph its about y = 0.6

- help_people

really quick whats the horizontal retricem and show me plesase who to solve

Looking for something else?

Not the answer you are looking for? Search for more explanations.