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vera_ewing
 one year ago
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vera_ewing
 one year ago
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Photon336
 one year ago
Best ResponseYou've already chosen the best response.2it's definitely not D. let me see. BTW do you have some kind of time limit for this?

Photon336
 one year ago
Best ResponseYou've already chosen the best response.2@Rushwr what do you think?

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.0thinking and reading now !

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.0what if we consider hydrolysis !

Photon336
 one year ago
Best ResponseYou've already chosen the best response.2I think i have it \[1.76x10^5 = \frac{ [x][x] }{ [0.28x] }\]

Photon336
 one year ago
Best ResponseYou've already chosen the best response.2Vera i got 2.65 ill show you how i got it

Photon336
 one year ago
Best ResponseYou've already chosen the best response.2\[ \sqrt{ }(1.76x10^5)*0.28 = 0.00221M = [H^+]\]

Photon336
 one year ago
Best ResponseYou've already chosen the best response.2pH = Log[H+] = Log[0.00221] = 2.65

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.0@Photon336 I agree I got the same answer

Photon336
 one year ago
Best ResponseYou've already chosen the best response.2you have to set up an ice table.. you know that CH3COOH > CH3COO + H+ \[\frac{ [CHCOO][H^+] }{ [CH3COOH]}\] \[\frac{ [+x][+x] }{ [CH3COOHx }\] concentration of CH3COOH will go down by x and the concentration of your acid and the conjugate base CH3COO will both be x. you can assume that because this is a weak acid we know we will have more of CH3COO so we can ignore the x here for CH3COO

Photon336
 one year ago
Best ResponseYou've already chosen the best response.2rearranges to give \[\frac{ x ^{2} }{ 0.28 } = 1.76x10^5\]
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