Discussion/Questions acids and bases

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Discussion/Questions acids and bases

Chemistry
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370/371/372
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373
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370. I will go with C Beacuse Strong acids don't form conjugated acids. They form conjugate base . The conjugate base for this is NO3^-1
371. I'll go with A \[Ka = \frac{ [H ]^{2} [S ^{2-}]}{ [H _{2}S] }\]
this is the Ka equation for the overall reaction.
i think it gives the Ka for the H2S
Ka1 = 1x10^-7 ka just compares exponents so it would be i think 7
To find Ka we have o multiply Ka1 and Ka2 and get the pKa
they say that because the second kA is so small you can just ignore it.
but wait is that what you are supposed to do? i forgot that
i'm just curious
IDK that but what I know is what I did . for 372 i'll go with D
wait it must be that then! What is the answer given for that is it 7?
373. it would be thymol blue !
Since it is a weak acid strong base titration the anionic hdrolysis occur making the medium basic at its equivalence point. Hence the pH increases !
going to leave this open coming back later.
oki doki
Well I thought 371 was supposed to be kind of like a trick question but then again I should probably review my acid base things. I thought we would say pKa of \(H_2S\) would be 7 and that the other value would be the value of the pKa of \(HS^-\).
372 seems fun one cause you really get to compare pKas of all these conjugate acids and bases. I guess the question is, which one of these answer choices is most basic?
@Woodward the solution said that because the second pKa was so small you could just ignore it.
\[K _{3}PO _{4} ---> PO _{4} +3K ^{+}\] |dw:1439180017859:dw| \[PO _{4} + H2O --> HPO4 + OH ^{-}\] not sure
372 not sure, think it would probably be the one that is most basic.
So the K+ ions are present in the solution right so won't it form KOH by combining with OH- ions. ?????? I am bad when it comes to inorganic. But what was the answer given? @Photon336
yeah well.. let me see for 372. the answer is C.
|dw:1439255147994:dw| |dw:1439255180440:dw| CH3CH2OH wouldn't raise the concentration of hydroxide ions, because it can't deprotinate water, don't think it's kb is that high. For basic compounds Kb > ka producing OH- ions the compound would have to act a as a base. and have a pKa that's higher than that of water, in -order to deprotinate it.
@Rushwr it's poorly written but the PO4 ion produces the most OH- ion concentration. in this case i think that the PO4 ion is acting as a base to deprotinate water and produce OH ions. it's pKa must be higher than water i think in order to deprotinate the water. this would imply that it's not really stable in solution.

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