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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Typo is there, right? x =332, y = 333, not x =333, right?
good catch
\(\large \color{black}{\begin{align} & \text{If}\ x=332,\ y=333,\ z=335 \hspace{.33em}\\~\\ & \text{then}\ (x^{3}+y^{3}+z^{3}-3xyz) \ \text{is equal to}\hspace{.33em}\\~\\~\\ & a.)\ 9000 \hspace{.33em}\\~\\ & b.)\ 10000 \hspace{.33em}\\~\\ & c.)\ 7000 \hspace{.33em}\\~\\ & d.)\ 8000 \hspace{.33em}\\~\\ \end{align}}\) I have to solve this within a minute

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Let's wait for @imqwerty
a^3 + b^3 + c^3 – 3abc = (a+b+c)((a-b)^2 + (b-c)^2 + (c-a)^2) /2 use this
wow how did he get that thing
the traditional method may take an hour
or their might be some other trick using \(y=x+1,z=x+2\)
What is the traditional method?
(traditional method)putting all those values and calculating
a^3 + b^3 +c^3 = (a+b+c)(a^2 +b^2 +c^2 -ab -bc -ca) =(a+b+c)(a^2 +a^2 +b^2 +b^2 +c^2 +c^2 -2ab-2bc-2ca)/2 did u get it now
yes i always forget the formula within 2 days

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