The average kinetic energy of 1 mole of a gas at -32 degrees Celsius is: 3.01 x 103 J 3.99 x 102 J -3.99 x 102 J 3.80 x 103 J

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

The average kinetic energy of 1 mole of a gas at -32 degrees Celsius is: 3.01 x 103 J 3.99 x 102 J -3.99 x 102 J 3.80 x 103 J

Chemistry
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

KE=(3/2)nRT Where KE is kinetic energy n is number of moles R is 8.31J/K T is temperature in Kelvin
What is the final answer? its okay this isn't a test. ill give u a medal lol @taramgrant0543664
KE=(3/2)(1.0)(8.31)(-32+273) KE=3004J KE=3.00x10^3J

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

If you use 273.15 then KE=3005 so rounding that to three significant digits it would be 3010 making it 3.01x10^3 in scientific notation

Not the answer you are looking for?

Search for more explanations.

Ask your own question