Calculate the discriminant and use it to determine how many real-number roots the equation has. 3x2 – 6x + 3 = 0 A. no real-number roots B. two real-number roots C. three real-number roots D. one real-number root

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Calculate the discriminant and use it to determine how many real-number roots the equation has. 3x2 – 6x + 3 = 0 A. no real-number roots B. two real-number roots C. three real-number roots D. one real-number root

Mathematics
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you dont have to help me i know the stuff i think i have the answer C
Alright, same way as before a=3, b=-6, and c=3 (-6)^2-4(3)(3)=36-36=0 Okay, the rule with dsicriminants is: If > 0: There are two real roots If = 0: There is one real root If < 0: There are two complex roots
The main reason it cannot be C is because the equation is a to the power of two meaning at most, it can only have 2 roots.
D
D is correct
thank you
Mhm

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