anonymous
  • anonymous
Calculate the discriminant and use it to determine how many real-number roots the equation has. 3x2 – 6x + 3 = 0 A. no real-number roots B. two real-number roots C. three real-number roots D. one real-number root
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
@happyrosy
anonymous
  • anonymous
@Michele_Laino @peachpi
anonymous
  • anonymous
@Mehek14

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anonymous
  • anonymous
you dont have to help me i know the stuff i think i have the answer C
anonymous
  • anonymous
Alright, same way as before a=3, b=-6, and c=3 (-6)^2-4(3)(3)=36-36=0 Okay, the rule with dsicriminants is: If > 0: There are two real roots If = 0: There is one real root If < 0: There are two complex roots
anonymous
  • anonymous
The main reason it cannot be C is because the equation is a to the power of two meaning at most, it can only have 2 roots.
anonymous
  • anonymous
D
anonymous
  • anonymous
D is correct
anonymous
  • anonymous
thank you
anonymous
  • anonymous
Mhm

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