vera_ewing
  • vera_ewing
.
Chemistry
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vera_ewing
  • vera_ewing
.
Chemistry
jamiebookeater
  • jamiebookeater
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Photon336
  • Photon336
I believe that the Kp will only depend on the concentration of the gaseous substances so you can basically ignore the solids. I believe
sweetburger
  • sweetburger
Yes solids will always fall out of the equilibrium constant. So will liquids.
Photon336
  • Photon336
Kp = [HI]^2/[H2S]

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Photon336
  • Photon336
Qp is the concentration of your reactants products at any point in your chemical reaction, before equilibrium has been established
taramgrant0543664
  • taramgrant0543664
At equilibrium, Q = K (the equilibrium constant for the reaction) Q = K is referred to as the equilibrium condition. If Q > K, the reverse reaction is favoured, the reaction moves from right to left, until equilibrium is established. If Q < K, the forward reaction is favoured, the reaction moves from left to right, until equilibrium is established.
Photon336
  • Photon336
Qp = (0.43)^2/(5.4) = 0.034 Kp if I remember was .130
Photon336
  • Photon336
It's gotta go to the right because Qp

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