anonymous
  • anonymous
@robtobey A geometric sequence is obtained by placing five terms between 10 and 640. What is the common ratio equal to ?
Algebra
jamiebookeater
  • jamiebookeater
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

jim_thompson5910
  • jim_thompson5910
If r is the common ratio, then what is the next term right after 10?
anonymous
  • anonymous
nothing the question was just like this
jim_thompson5910
  • jim_thompson5910
do you agree that it would be 10*r or 10r ?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

jim_thompson5910
  • jim_thompson5910
since to get the next term, you multiply the last term by r hopefully that makes sense
anonymous
  • anonymous
nope mate the answer will be 4 2 3 5 or 6
jim_thompson5910
  • jim_thompson5910
don't worry about the answer choices right now
anonymous
  • anonymous
ok
anonymous
  • anonymous
11
jim_thompson5910
  • jim_thompson5910
idk what you mean the term that comes after 10 is 10r the term after 10r is 10r*r = 10r^2 etc etc until you get to 640
jim_thompson5910
  • jim_thompson5910
you should get this sequence: 10, 10r, 10r^2, 10r^3, 10r^4, 10r^5, 640
anonymous
  • anonymous
ok
jim_thompson5910
  • jim_thompson5910
the next term after 10r^5 is 10r^6 therefore, 10r^6 = 640
jim_thompson5910
  • jim_thompson5910
solve 10r^6 = 640 for r to get your answer
anonymous
  • anonymous
which is 4
zzr0ck3r
  • zzr0ck3r
I agree, to see an example look at 1,2,4,8,16,32,64 64/1=2^6
jim_thompson5910
  • jim_thompson5910
r = 4 is false
anonymous
  • anonymous
sorry it will be 2
jim_thompson5910
  • jim_thompson5910
r = 2 is true
anonymous
  • anonymous
thanks man can I ask 1 more question
jim_thompson5910
  • jim_thompson5910
sure
anonymous
  • anonymous
thank you then now I am writing
anonymous
  • anonymous
|dw:1439165401472:dw|
anonymous
  • anonymous
Did you get the question because my drawing is not good enough ?
jim_thompson5910
  • jim_thompson5910
what is the area of the circle given
jim_thompson5910
  • jim_thompson5910
hint: use A = pi*r^2
anonymous
  • anonymous
it has given no area
jim_thompson5910
  • jim_thompson5910
use that formula I gave to compute the area
jim_thompson5910
  • jim_thompson5910
r = 5 in this case
anonymous
  • anonymous
ok but how
jim_thompson5910
  • jim_thompson5910
A = pi*r^2 A = pi*5^2 A = ???
anonymous
  • anonymous
25pi then wat will happen
jim_thompson5910
  • jim_thompson5910
now we will have another circle with the same center at point A this new circle will have radius 3 |dw:1439165882115:dw|
anonymous
  • anonymous
ok
jim_thompson5910
  • jim_thompson5910
the goal is to find the area of this shaded region and divide it by the 25pi found earlier |dw:1439165892979:dw|
jim_thompson5910
  • jim_thompson5910
what is the area of the smaller circle?
anonymous
  • anonymous
9pi
anonymous
  • anonymous
but the answer is not 9/25 mate
jim_thompson5910
  • jim_thompson5910
it would be 9pi/25pi = 9/25 IF we wanted to land inside the inner circle but we want to land in that ring I shaded above
jim_thompson5910
  • jim_thompson5910
area of ring = (area of larger circle) - (area of smaller circle)
jim_thompson5910
  • jim_thompson5910
answer = (area of ring)/(area of larger circle)
anonymous
  • anonymous
yes which will be 16/25
jim_thompson5910
  • jim_thompson5910
good
anonymous
  • anonymous
can I ask more please
jim_thompson5910
  • jim_thompson5910
one last one
anonymous
  • anonymous
ok
anonymous
  • anonymous
1 Attachment
jim_thompson5910
  • jim_thompson5910
which one?
anonymous
  • anonymous
10
anonymous
  • anonymous
if you can all of them :D
jim_thompson5910
  • jim_thompson5910
are you able to compute f ' (x) ?
anonymous
  • anonymous
not at all
jim_thompson5910
  • jim_thompson5910
|dw:1439166519002:dw|
jim_thompson5910
  • jim_thompson5910
what is the derivative of sin(x) ?
anonymous
  • anonymous
cosx
jim_thompson5910
  • jim_thompson5910
so we just derive the outer function sin(...) to get cos(...) |dw:1439166578842:dw|
jim_thompson5910
  • jim_thompson5910
then we use the chain rule to derive cos(x) to get -sin(x) so derive cos(...) to get -sin(...) that gets multiplied to what we have |dw:1439166647000:dw|
jim_thompson5910
  • jim_thompson5910
we then go in further derive 5x to get 5 that gets tacked on too |dw:1439166679192:dw| I placed it up front
anonymous
  • anonymous
ok
jim_thompson5910
  • jim_thompson5910
so \[\Large f \ ' (x) = 5\cos(\cos(5x))*(-\sin(5x))\]
jim_thompson5910
  • jim_thompson5910
now just replace every x with pi/10 and evaluate
anonymous
  • anonymous
ok
anonymous
  • anonymous
the answer I think will be -5
jim_thompson5910
  • jim_thompson5910
yep it's -5
anonymous
  • anonymous
can I PLease PLease ask one more question
anonymous
  • anonymous
just one more and thats it
anonymous
  • anonymous
thank you
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
57
anonymous
  • anonymous
did you find the answer mate
anonymous
  • anonymous
Recall that \(sec^2(x) - tan^2(x) =1 \) \(cos^2(x) - cos(x)sin(x) = cos^2(x)[1 - tanx] = \frac{1}{sec^2(x)}[1-tanx] = \frac{1}{1+tan^2(x)}[1-tan(x)]\) Now put the value of tan(x) that's given.
anonymous
  • anonymous
ok carry on
anonymous
  • anonymous
* \(\frac{1}{1+tan^2(x)}[1-tan(x)]\)
anonymous
  • anonymous
yeah but thats not my answer
anonymous
  • anonymous
Substitute the tan(x)= 2 and get the answer.
anonymous
  • anonymous
wat you think will be the answer

Looking for something else?

Not the answer you are looking for? Search for more explanations.