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anonymous

  • one year ago

*** help*** a new exhibit is scheduled to open at the local museum. museum officials expect that 5000 people will visit the exhibit in its first week, and that the number of visitors will drop by 10 people per week after the first week during the first 6 months. find the total number of visitors expected in the exhibits first 7 weeks

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  1. mathstudent55
    • one year ago
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    In the first week there will be 5000 visitors. In the second week, there will be 10% fewer visitors than in the first week. Can you calculate how many visitors there will be in the second week?

  2. anonymous
    • one year ago
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    5000/.10=50000

  3. anonymous
    • one year ago
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    right?

  4. anonymous
    • one year ago
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    @mathstudent55

  5. mathstudent55
    • one year ago
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    No. In math, in addition to solving a problem using some method, you need to look at your answer and see if it makes sense. If there will be 10% FEWER visitors in the second week, how can you end up with 10 times more visitors?

  6. mathstudent55
    • one year ago
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    This is how you do it.

  7. mathstudent55
    • one year ago
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    In the first week, there are 5000 visitors. Call the initial number, 5000, 100%. In the second week, there will be 10% fewer visitors. That means in the second week, there will be 100% - 10% = 90% of the 5000 visitors.

  8. mathstudent55
    • one year ago
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    Now we calculate 90% of 5000. 90% of 5000 = 90/100 * 5000 = 0.90 * 5000 = 4500

  9. anonymous
    • one year ago
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    ok

  10. mathstudent55
    • one year ago
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    Ok so far?

  11. anonymous
    • one year ago
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    correct

  12. anonymous
    • one year ago
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    but the number that you're getting is decreasing. the answer choices are, 34,730, 24,850, 34790, 29,850

  13. mathstudent55
    • one year ago
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    |dw:1439166621075:dw|

  14. anonymous
    • one year ago
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    so it goes down by 500

  15. mathstudent55
    • one year ago
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    You see the table above. That is where we are so far in solving this problem. We know how many visitors there will be in the first and second weeks. Now we need to find the numbers for weeks 3 through 7. Then we add all numbers up.

  16. anonymous
    • one year ago
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    ok got you!

  17. mathstudent55
    • one year ago
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    You asked a good question. The answer is no. The number goes down by 10% of the previous week. Since the first week has 5000 visitors, 10% of 5000 is 500, so from week 1 to week 2 it went down by 500.

  18. mathstudent55
    • one year ago
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    Now to find the number for week 3, think of week 2 as 100%. What is 90% of 4500?

  19. anonymous
    • one year ago
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    4050

  20. anonymous
    • one year ago
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    .90*4500

  21. mathstudent55
    • one year ago
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    You are always losing 10% of the previous week, but each week, the number is decreasing, so 10% of the previous week is going to be less and less each week that goes by.

  22. mathstudent55
    • one year ago
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    Exactly. You put it on our table. |dw:1439167056423:dw|

  23. mathstudent55
    • one year ago
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    Now start with 4050, and find 90% of that number. 0.90 * 4050 = 3645 |dw:1439167103110:dw|

  24. mathstudent55
    • one year ago
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    You see how you get the following week's number? Multiply each week's number by 0.9 Fill in the table's right column. Then add all numbers in the right column.

  25. anonymous
    • one year ago
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    ok doing it now.

  26. anonymous
    • one year ago
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    i ended up getting 22440.155

  27. anonymous
    • one year ago
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    |dw:1439167568272:dw|

  28. mathstudent55
    • one year ago
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    |dw:1439167579583:dw|

  29. mathstudent55
    • one year ago
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    I get 26,085. The problem is the answer is not in your choices.

  30. anonymous
    • one year ago
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    ok i had a typo

  31. mathstudent55
    • one year ago
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    Are you sure you copied the problem correctly?

  32. mathstudent55
    • one year ago
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    Ok

  33. anonymous
    • one year ago
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    and yes, thats what im trying to see.

  34. anonymous
    • one year ago
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    yes, it's copied word from word.

  35. mathstudent55
    • one year ago
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    Are you sure the number goes down 10% each week. There is a percent in the problem?

  36. mathstudent55
    • one year ago
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    Wait. I'm the one who misread your problem.

  37. anonymous
    • one year ago
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    10 people per week

  38. mathstudent55
    • one year ago
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    I just reread it. The problem states the number goes down 10 people per week. I read it as 10 percent per week. My mistake. Sorry about that.

  39. anonymous
    • one year ago
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    lol it's fine. thank you for being patient with me. math gives me a headache

  40. mathstudent55
    • one year ago
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    That means it's a simpler problem. Let's use the same table, and clear out the second column except for the 5000 in the first week.

  41. anonymous
    • one year ago
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    ok cool

  42. mathstudent55
    • one year ago
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    |dw:1439168119386:dw|

  43. mathstudent55
    • one year ago
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    Now for each subsequent week, we just subtract 10 from the previous week. As you can see, this is an easier problem than I thought because of my misreading.

  44. anonymous
    • one year ago
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    |dw:1439168175356:dw|

  45. anonymous
    • one year ago
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    are you serious? lol i feel so dumb

  46. anonymous
    • one year ago
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    that was easy but reading it, i thought that i had to do more

  47. mathstudent55
    • one year ago
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    |dw:1439168205828:dw|

  48. mathstudent55
    • one year ago
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    Good job! Exactly. That's what I got. As you can see, it's not a difficult problem. Sorry to have complicated it above.

  49. anonymous
    • one year ago
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    lol no it's perfectly fine. i appreciate your help and patience

  50. mathstudent55
    • one year ago
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    You're very welcome.

  51. anonymous
    • one year ago
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    thank you! i have more problems, but i wont burden you. ill try to work them out first, but thank you!

  52. mathstudent55
    • one year ago
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    1. You are welcome. 2. Try your problems by yourself first. If you need help, don't hesitate to ask for it. 3. Helping is not a burden.

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