anonymous
  • anonymous
*** help*** a new exhibit is scheduled to open at the local museum. museum officials expect that 5000 people will visit the exhibit in its first week, and that the number of visitors will drop by 10 people per week after the first week during the first 6 months. find the total number of visitors expected in the exhibits first 7 weeks
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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mathstudent55
  • mathstudent55
In the first week there will be 5000 visitors. In the second week, there will be 10% fewer visitors than in the first week. Can you calculate how many visitors there will be in the second week?
anonymous
  • anonymous
5000/.10=50000
anonymous
  • anonymous
right?

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anonymous
  • anonymous
@mathstudent55
mathstudent55
  • mathstudent55
No. In math, in addition to solving a problem using some method, you need to look at your answer and see if it makes sense. If there will be 10% FEWER visitors in the second week, how can you end up with 10 times more visitors?
mathstudent55
  • mathstudent55
This is how you do it.
mathstudent55
  • mathstudent55
In the first week, there are 5000 visitors. Call the initial number, 5000, 100%. In the second week, there will be 10% fewer visitors. That means in the second week, there will be 100% - 10% = 90% of the 5000 visitors.
mathstudent55
  • mathstudent55
Now we calculate 90% of 5000. 90% of 5000 = 90/100 * 5000 = 0.90 * 5000 = 4500
anonymous
  • anonymous
ok
mathstudent55
  • mathstudent55
Ok so far?
anonymous
  • anonymous
correct
anonymous
  • anonymous
but the number that you're getting is decreasing. the answer choices are, 34,730, 24,850, 34790, 29,850
mathstudent55
  • mathstudent55
|dw:1439166621075:dw|
anonymous
  • anonymous
so it goes down by 500
mathstudent55
  • mathstudent55
You see the table above. That is where we are so far in solving this problem. We know how many visitors there will be in the first and second weeks. Now we need to find the numbers for weeks 3 through 7. Then we add all numbers up.
anonymous
  • anonymous
ok got you!
mathstudent55
  • mathstudent55
You asked a good question. The answer is no. The number goes down by 10% of the previous week. Since the first week has 5000 visitors, 10% of 5000 is 500, so from week 1 to week 2 it went down by 500.
mathstudent55
  • mathstudent55
Now to find the number for week 3, think of week 2 as 100%. What is 90% of 4500?
anonymous
  • anonymous
4050
anonymous
  • anonymous
.90*4500
mathstudent55
  • mathstudent55
You are always losing 10% of the previous week, but each week, the number is decreasing, so 10% of the previous week is going to be less and less each week that goes by.
mathstudent55
  • mathstudent55
Exactly. You put it on our table. |dw:1439167056423:dw|
mathstudent55
  • mathstudent55
Now start with 4050, and find 90% of that number. 0.90 * 4050 = 3645 |dw:1439167103110:dw|
mathstudent55
  • mathstudent55
You see how you get the following week's number? Multiply each week's number by 0.9 Fill in the table's right column. Then add all numbers in the right column.
anonymous
  • anonymous
ok doing it now.
anonymous
  • anonymous
i ended up getting 22440.155
anonymous
  • anonymous
|dw:1439167568272:dw|
mathstudent55
  • mathstudent55
|dw:1439167579583:dw|
mathstudent55
  • mathstudent55
I get 26,085. The problem is the answer is not in your choices.
anonymous
  • anonymous
ok i had a typo
mathstudent55
  • mathstudent55
Are you sure you copied the problem correctly?
mathstudent55
  • mathstudent55
Ok
anonymous
  • anonymous
and yes, thats what im trying to see.
anonymous
  • anonymous
yes, it's copied word from word.
mathstudent55
  • mathstudent55
Are you sure the number goes down 10% each week. There is a percent in the problem?
mathstudent55
  • mathstudent55
Wait. I'm the one who misread your problem.
anonymous
  • anonymous
10 people per week
mathstudent55
  • mathstudent55
I just reread it. The problem states the number goes down 10 people per week. I read it as 10 percent per week. My mistake. Sorry about that.
anonymous
  • anonymous
lol it's fine. thank you for being patient with me. math gives me a headache
mathstudent55
  • mathstudent55
That means it's a simpler problem. Let's use the same table, and clear out the second column except for the 5000 in the first week.
anonymous
  • anonymous
ok cool
mathstudent55
  • mathstudent55
|dw:1439168119386:dw|
mathstudent55
  • mathstudent55
Now for each subsequent week, we just subtract 10 from the previous week. As you can see, this is an easier problem than I thought because of my misreading.
anonymous
  • anonymous
|dw:1439168175356:dw|
anonymous
  • anonymous
are you serious? lol i feel so dumb
anonymous
  • anonymous
that was easy but reading it, i thought that i had to do more
mathstudent55
  • mathstudent55
|dw:1439168205828:dw|
mathstudent55
  • mathstudent55
Good job! Exactly. That's what I got. As you can see, it's not a difficult problem. Sorry to have complicated it above.
anonymous
  • anonymous
lol no it's perfectly fine. i appreciate your help and patience
mathstudent55
  • mathstudent55
You're very welcome.
anonymous
  • anonymous
thank you! i have more problems, but i wont burden you. ill try to work them out first, but thank you!
mathstudent55
  • mathstudent55
1. You are welcome. 2. Try your problems by yourself first. If you need help, don't hesitate to ask for it. 3. Helping is not a burden.

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