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anonymous

  • one year ago

Find the slope of the tangent line to the polar curve r=sin(4θ) at θ=π/8.

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  1. jim_thompson5910
    • one year ago
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    this page may be of help http://tutorial.math.lamar.edu/Classes/CalcII/PolarTangents.aspx

  2. anonymous
    • one year ago
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    still am confused

  3. jim_thompson5910
    • one year ago
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    where are you stuck in the article?

  4. anonymous
    • one year ago
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    it has cos and ii am trying to find (sin) in my problem

  5. jim_thompson5910
    • one year ago
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    x = r*cos(theta) x = sin(4theta) * cos(theta) ... replace 'r' with 'sin(4theta)' what do you get when you derive both sides with respect to theta?

  6. anonymous
    • one year ago
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    r/r*cos ??

  7. jim_thompson5910
    • one year ago
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    if the theta's are throwing you off, then think of them as x ie think of it as y = sin(4x)*cos(x) what is dy/dx here?

  8. anonymous
    • one year ago
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    idk

  9. jim_thompson5910
    • one year ago
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    use the product and chain rule here

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