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anonymous
 one year ago
Simplify.. need help asap...
8/ab + 6/b
and
(3t2/(t + 2)) x ((t + 2)/t2)
thanks!!
anonymous
 one year ago
Simplify.. need help asap... 8/ab + 6/b and (3t2/(t + 2)) x ((t + 2)/t2) thanks!!

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jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0The first one is \[\Large \frac{8}{ab} + \frac{6}{b}\] right?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0what is the LCD in this case?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0we have ab as the first denominator and b as the second denominator

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0do you see how the LCD would be ab?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0:( I'm really bad at math. I'm sorry..

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0maybe replace a and b with numbers

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0say a = 2 b = 3

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0if we had 1/6 + 1/3, what would the LCD be?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0yes because we can multiply the denominator 3 by 2 to get 6

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0we can multiply top and bottom of 1/3 by 2 to get 2/6 1/6 + 1/3 turns into 1/6 + 2/6

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0from there you add straight across and leave the denominator alone

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0the same idea applies here we multiply top and bottom of the second fraction by 'a' \[\Large \frac{8}{ab} + \frac{6}{b}\] \[\Large \frac{8}{ab} + \frac{6{\color{red}{a}}}{b{\color{red}{a}}}\] \[\Large \frac{8}{ab} + \frac{6a}{ab}\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0then you add the numerators and place that over the denominator

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how do we find the answer? or did we already find it and i was lost before then? i thought I've been following.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0do you see why I multiplied top and bottom of the second fraction by 'a'?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0I wanted to get every denominator equal to the LCD 'ab'

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0there's one more step to go

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0What does \[\Large \frac{8}{ab} + \frac{6a}{ab}\] simplify to?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0just add up the numerators \[\Large \frac{8}{ab} + \frac{6a}{ab}=\frac{8+6a}{ab}\] this is possible because the denominators are both equal to ab

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay. now how would we do the second one?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0The second one is \[\Large \left(\frac{3t^2}{t+2}\right)\times\left(\frac{t+2}{t^2}\right)\] right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0t+2 on the sec on one are in a parenthesis.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and in the first one. its like parenthesis insides of themselves.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0ok so this? \[\Large \left(\frac{3t^2}{(t+2)}\right)\times\left(\frac{(t+2)}{t^2}\right)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes that is correct.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0first notice this cancellation \[\Large \left(\frac{3{\color{red}{\cancel{\color{black}{t^2}}}}}{t+2}\right)\times\left(\frac{t+2}{{\color{red}{\cancel{\color{black}{t^2}}}}}\right)\] the t^2 terms will go away leaving just \[\Large \left(\frac{3}{(t+2)}\right)\times\left(\frac{(t+2)}{1}\right)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok what is the next step

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0then the (t+2) terms also cancel \[\Large \left(\frac{3}{{\color{red}{\cancel{\color{black}{(t+2)}}}}}\right)\times\left(\frac{{\color{red}{\cancel{\color{black}{(t+2)}}}}}{1}\right)\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0I'm sure you see how to finish

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thats the easiest thing I've ever seen
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