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vera_ewing
 one year ago
Chem question
vera_ewing
 one year ago
Chem question

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0are you familiar with the graph: \[y=\frac{1}{x}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Awesome, cause that's what you're looking at here basically. So if you rearrange it, you can write the same exact equation for that graph as \(yx=1\) This tells you what you need to look for in the relation \(PV=nRT\) the two quantities represented by that graph will end up being on the same side of this equation.

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.2Temperature and pressure are not on the same side of the ideal gas equation

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.2If temperature increases pressure should also increase so it should have a positive slope not negative

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.2If pressure is increased volume would decrease so yes that is your answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah, so you can kinda just say that \(nRT=1\) or something, it won't really change the relationship between P and V, \[P=\frac{nRT}{V}\] Or you can put it back in there to see: \[P=\frac{1}{V}\]
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