## anonymous one year ago (Will give medal to the person who helps) Find the ratio of x to y. ~ x/5 = 2/3 = 5/y ~ 1.) 2/3 2.) 4/9 3.) 1

1. mathstudent55

Use x/5 = 2/3 to solve for x. It's a proportion, so cross multiply.

2. anonymous

Alright I tried it , but I came out with decimal. Is that ok or ?

3. mathstudent55

|dw:1439168515677:dw|

4. mathstudent55

It's better to leave it as a fraction like I did above.

5. anonymous

wait nvm I looked at it wrong

6. mathstudent55

Do you see what I did to solve for x? I used the first two fractions as a proportion, and solved the proportion for x. Are you ok so far?

7. anonymous

yea I am ~

8. mathstudent55

Great. Now take the second and third fractions, and use them as a proportion and solve for y.

9. mathstudent55

Now cross multiply and solve the proportion below for y. |dw:1439168686577:dw|

10. anonymous

2y = 15

11. anonymous

right ??

12. mathstudent55

good so far Now solve for y

13. mathstudent55

Leave the result as a fraction.

14. anonymous

\[15 \div 2 ?? \]

15. mathstudent55

|dw:1439168922451:dw|

16. mathstudent55

Yes, 15 divided by 2 is simply the fraction 15/2.

17. mathstudent55

Now we want the ratio of x to y. The ratio of x to y can be written as x:y, and also as the fraction \(\dfrac{x}{y} \)

18. anonymous

do we cross multiply them now ? the x y ?

19. mathstudent55

Since we know what x and y are equal to, we write a ratio using those two numbers: |dw:1439169044897:dw|

20. mathstudent55

|dw:1439169083196:dw|

21. anonymous

thats none of my choices ~

22. mathstudent55

We haven't finished yet. We now have a complex fraction, a fraction of fractions. We need to simplify it. Remember that a fraction means a division. |dw:1439169173036:dw|

23. mathstudent55

To divide fractions, we multiply the first fraction by the reciprocal of the second one. Reciprocal is the math term that means to flip the fraction.

24. mathstudent55

|dw:1439169248633:dw|

25. mathstudent55

|dw:1439169310000:dw|

26. anonymous

ohhh I see ! ~ :)

27. mathstudent55

Great!

28. anonymous

i understand now ! thanks !

29. mathstudent55

You're welcome.