A spinner and 6 cards are shown below: A spinner with 3 equal sectors is shown in the figure. The colors Green, Blue, and Red are marked on it. The arrow points at the green color. Six cards are shown on the right side. The colors Purple, Green, Red, Yellow, Blue, and Pink are marked on them. Jordan spins the spinner and picks up a card without looking. What is the probability that the spinner stops at green and a yellow card is selected? Answers are 1/36 , 1/18 , 1/6 1/3 I think its one 1/6?

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A spinner and 6 cards are shown below: A spinner with 3 equal sectors is shown in the figure. The colors Green, Blue, and Red are marked on it. The arrow points at the green color. Six cards are shown on the right side. The colors Purple, Green, Red, Yellow, Blue, and Pink are marked on them. Jordan spins the spinner and picks up a card without looking. What is the probability that the spinner stops at green and a yellow card is selected? Answers are 1/36 , 1/18 , 1/6 1/3 I think its one 1/6?

Probability
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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what's the probability the spinner lands on green
not sure
probability the spinner lands on green = (# of green spaces)/(# of total spaces)

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Other answers:

8
you have 3 sectors and only 1 green out of the three
ok
probability the spinner lands on green = ??
it will be a fraction
1/3
yes
now what is the probability of picking a yellow card?
hmm 1
it will be a fraction
probability of picking yellow card = (# of yellow cards)/(# of cards total)
1/6
yes
now multiply the two probabilities 1/3 and 1/6
1/18
correct
yes thank you some much jim!!
glad to be of help

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