Find f(x) and g(x) so that the function can be described as y = f(g(x)).

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Find f(x) and g(x) so that the function can be described as y = f(g(x)).

Mathematics
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f(x)=\[\frac{ 2 }{ x^{2} }\]

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Your pick for f(x) won't work because you need the x part to be with g(x). You can choose g(x) = 2/x² though because it's the inside function
Then f(x) is the outside function, so it would be like you substituted 2/x² in for the x in f(x) = x + 9
so f(x)=x+9 f(2/(x^2))=(2/(x^2))+9 is wrong?
that's right because g(x) = 2/x²
so when g(x) = 2/x², the x in f(x) = x + 9 f(2/x²)=2/x², +9?
yes that's correct
thank you
so i just write
1) Don't use \(y\) as \(y\) here is actually \(f(g(x))\). So just use \(f(x) \) and \(g(x)\) 2) What you wrote in that last post is not what you wrote before, the latter is incorrect. You want \(f(x) = x+9\) and \(g(x) = \dfrac{2}{x^2}\). Now we have \(f(g(x)) = f(\dfrac{2}{x^2})= \dfrac{2}{x^2}+9\) as desired.
I think I misunderstood what you were saying. f(x) = x + 9 g(x) = 2/x² The function f(g(x)) = (2/x²) + 9 is a composed function made up of both f(x) and g(x).
so just this: f(x) and g(x) so that the function can be described as y = f(g(x)). f(x)= 2/x²+ 9 g(x) = 2/x²
p.s. If you would like to be a smart retriceon the test, there is always one answer that will work. Let \(g(x) = \frac{2}{x^2}+9\) and let \(f(x) = x\), or vice versa. This will always work :)
that should say "smart a**"

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