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anonymous
 one year ago
Find f(x) and g(x) so that the function can be described as y = f(g(x)).
anonymous
 one year ago
Find f(x) and g(x) so that the function can be described as y = f(g(x)).

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0f(x)=\[\frac{ 2 }{ x^{2} }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Your pick for f(x) won't work because you need the x part to be with g(x). You can choose g(x) = 2/x² though because it's the inside function

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Then f(x) is the outside function, so it would be like you substituted 2/x² in for the x in f(x) = x + 9

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so f(x)=x+9 f(2/(x^2))=(2/(x^2))+9 is wrong?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that's right because g(x) = 2/x²

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so when g(x) = 2/x², the x in f(x) = x + 9 f(2/x²)=2/x², +9?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.11) Don't use \(y\) as \(y\) here is actually \(f(g(x))\). So just use \(f(x) \) and \(g(x)\) 2) What you wrote in that last post is not what you wrote before, the latter is incorrect. You want \(f(x) = x+9\) and \(g(x) = \dfrac{2}{x^2}\). Now we have \(f(g(x)) = f(\dfrac{2}{x^2})= \dfrac{2}{x^2}+9\) as desired.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think I misunderstood what you were saying. f(x) = x + 9 g(x) = 2/x² The function f(g(x)) = (2/x²) + 9 is a composed function made up of both f(x) and g(x).

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so just this: f(x) and g(x) so that the function can be described as y = f(g(x)). f(x)= 2/x²+ 9 g(x) = 2/x²

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1p.s. If you would like to be a smart retriceon the test, there is always one answer that will work. Let \(g(x) = \frac{2}{x^2}+9\) and let \(f(x) = x\), or vice versa. This will always work :)

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1that should say "smart a**"
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