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anonymous
 one year ago
Write the complex number in the form a + bi.
square root of six(cos 315° + i sin 315°)
anonymous
 one year ago
Write the complex number in the form a + bi. square root of six(cos 315° + i sin 315°)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I dont know how to solve this at all... My choices: square root of three over two minus square root of thee over two times i square root of six minus square root of sixi square root of three minus square root of threei square root of six over two minus square root of six over two times i

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1look at the unit circle cos 315 = what ? remember (x,y) sin =ycoordinate and cos = xcoordinate

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0cos315 is square root(2)/2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so \[\frac{ \sqrt{2} }{ 2 }\] is my x coordinate?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes, I was just looking at that

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge\rm \sqrt{6}(\cos 315° + i \sin 315°)\] so cos 315 =sqrt{2} over 2 replace cos 315 by that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So i would replace isin315 with \[\frac{ \sqrt{2} }{ 2 }\]

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0@Nnesha Good job!! open my eye!! :)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge\rm \sqrt{6}(\color{reD}{cos 315°} + i \sin 315°)\] \[\sqrt{6}(\frac{ \sqrt{2} }{ 2 }+i (\frac{ \sqrt{2} }{ 2 }))\] ust sin315 not the i

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright, then do I distribute the \[\sqrt{6}\]?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1first distribute by i i times sqrt{2} over 2

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\sqrt{6}(\frac{ \sqrt{2} }{ 2}  \frac{ \sqrt{2} }{ 2}i)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, after distributing i, do I distribute the square root of 6?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1well i wouldn't do that just take out the common factor

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\sqrt{6}\color{ReD}{(\frac{ \sqrt{2} }{ 2}  \frac{ \sqrt{2} }{ 2}i)}\] what is common factor in the parentheses

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hmm... then my end result is \[\sqrt{3}(i+1)\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1u sure or just guessing ? ;P

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0100% sure. I just calculated it. If I distribute the square root of 3, then I get what appears to be my third choice. Am I correct?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1alright yes that's correct there are square roots that's why i don't like distributing by sqrt{6} you can take out the common factor which is sqrt{2}/2

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\sqrt{6} \times \frac{ \sqrt{2} }{ 2 }(1i)\] \[\frac{ \sqrt{12} }{ 2 }(1i)\]multply sqrt{6} times sqrt{2} now factor 12 \[\frac{ \sqrt{4 \times 3} }{ 2}(1i)\] take the square root of 2 you will get the same answer

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1i found it easy but you can apply any method as lng s you get the same answer
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