## avountae2003 one year ago I have these on my study guide but for some reason I keep getting them wrong can someone break it down for me. 1. 2+4(x-7)=7-5(x-4) 2. 2(5z-1)-2(z+9)=3(z+1) This one is a fraction: -5/9x+2/3=5/9

1. anonymous

can you show how you did these?

2. avountae2003

1. 2+4x-28=7-5x+20 4x-26=27+5x +26 4x=53+5x -5x 9x=53 /9 53/9=x

3. avountae2003

2. 10z-2-2z-18=3z+3 8z-20=3z+3 +20 8z=3z+23 -3 5z=23 /5 23/5=z

4. avountae2003

Thats all I know because the fraction one I dont understand at all.

5. anonymous

ok. give me a sec

6. avountae2003

ok

7. mathstudent55

1. 2+4x-28=7-5x+20 4x-26=27+5x ^ | how did this become +? It was - in the line abnove.

8. mathstudent55

^above

9. avountae2003

oh I accidentally changed it

10. mathstudent55

Interestingly, later you made another mistake, and the answer came out correct.

11. anonymous

I ended up with the same thing you did for both.

12. mathstudent55

1. 2 + 4x - 28 = 7 - 5x + 20 4x - 26 = 27 - 5x +5x +5x ------------------ 9x - 26 = 27 + 26 +26 -------------- 9x = 53 x = 53/9

13. avountae2003

When I put them in my study it guide it say I have done it wrong.

14. mathstudent55

Your final answer to problem 1 is correct, but you made two mistakes which somehow canceled each other.

15. avountae2003

okay could you show me what I did wrong

16. mathstudent55

Problem 2. 2(5z-1)-2(z+9)=3(z+1) 10z-2-2z-18=3z+3 <---- correct 8z-20=3z+3 <----- correct +20 --------------- 8z=3z+23 <------- correct -3 <----- should read -3z 5z=23 /5 23/5=z <----- correct final answer

17. mathstudent55

You did problem 2 well.

18. avountae2003

Thank you but for some reason it is wrong

19. anonymous

For the third one is it like this with the x beside -5/9? just want to make sure it's not in the denominator $-\frac{ 5 }{ 9 }x+\frac{ 2 }{ 3 }=\frac{ 5 }{ 9}$

20. mathstudent55

21. avountae2003

Yes peachpi and it ask for a integer or simplified fraction

22. anonymous

ok. you can do the same thing you did for the others. Start by subtracting 2/3 from both sides, then you'll need to get a common denominator to subtract the fractions. |dw:1439177420232:dw|

23. avountae2003

ok do I find the common denominator on both fractions or just change one?

24. anonymous

you only have to change the 2/3 to ninths

25. avountae2003

ok now I see thank you. The first two problem though are still wrong

26. anonymous

I don't know what they're looking for. Your work is correct other than the sign errors on the first problem.

27. avountae2003

okay thank you for the help