I have these on my study guide but for some reason I keep getting them wrong can someone break it down for me.
1. 2+4(x7)=75(x4)
2. 2(5z1)2(z+9)=3(z+1)
This one is a fraction:
5/9x+2/3=5/9
 avountae2003
I have these on my study guide but for some reason I keep getting them wrong can someone break it down for me.
1. 2+4(x7)=75(x4)
2. 2(5z1)2(z+9)=3(z+1)
This one is a fraction:
5/9x+2/3=5/9
 katieb
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 anonymous
can you show how you did these?
 avountae2003
1. 2+4x28=75x+20
4x26=27+5x
+26
4x=53+5x
5x
9x=53
/9
53/9=x
 avountae2003
2. 10z22z18=3z+3
8z20=3z+3
+20
8z=3z+23
3
5z=23
/5
23/5=z
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 avountae2003
Thats all I know because the fraction one I dont understand at all.
 anonymous
ok. give me a sec
 avountae2003
ok
 mathstudent55
1. 2+4x28=75x+20
4x26=27+5x
^

how did this become +? It was  in the line abnove.
 mathstudent55
^above
 avountae2003
oh I accidentally changed it
 mathstudent55
Interestingly, later you made another mistake, and the answer came out correct.
 anonymous
I ended up with the same thing you did for both.
 mathstudent55
1. 2 + 4x  28 = 7  5x + 20
4x  26 = 27  5x
+5x +5x

9x  26 = 27
+ 26 +26

9x = 53
x = 53/9
 avountae2003
When I put them in my study it guide it say I have done it wrong.
 mathstudent55
Your final answer to problem 1 is correct, but you made two mistakes which somehow canceled each other.
 avountae2003
okay could you show me what I did wrong
 mathstudent55
Problem 2.
2(5z1)2(z+9)=3(z+1)
10z22z18=3z+3 < correct
8z20=3z+3 < correct
+20

8z=3z+23 < correct
3 < should read 3z
5z=23
/5
23/5=z < correct final answer
 mathstudent55
You did problem 2 well.
 avountae2003
Thank you but for some reason it is wrong
 anonymous
For the third one is it like this with the x beside 5/9? just want to make sure it's not in the denominator
\[\frac{ 5 }{ 9 }x+\frac{ 2 }{ 3 }=\frac{ 5 }{ 9}\]
 mathstudent55
The answer is correct. Do they ask for a decimal instead of a fraction?
 avountae2003
Yes peachpi and it ask for a integer or simplified fraction
 anonymous
ok. you can do the same thing you did for the others. Start by subtracting 2/3 from both sides, then you'll need to get a common denominator to subtract the fractions.
dw:1439177420232:dw
 avountae2003
ok do I find the common denominator on both fractions or just change one?
 anonymous
you only have to change the 2/3 to ninths
 avountae2003
ok now I see thank you. The first two problem though are still wrong
 anonymous
I don't know what they're looking for. Your work is correct other than the sign errors on the first problem.
 avountae2003
okay thank you for the help
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