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Do you have an idea on how to do this?

I think I do somewhat

factor out the like terms for
\[5x^2+60x=0\]

Aren't I supposed to find what 5^2 and 60 have in common or something like that or I am mistaken ._.

yeah.... you are supposed to find what they have in common and yank em out.

To find the second number you have to factor out what you can so what can you factor out?

They both have 5x in common so you can factor that out

So 5x(x+12)=0

how is 3 x 3 12?
3 x 3 = 9

I meant 3 times 4 sorry

To get the inside the brackets equal to 0 how do you get that?

By subtracting because we want less?

Solve both for x

x = 0 its so simple ._.

5x = 0 (divide)
x +12 = 0 (sibtract)

(X+12)=0 you want some number to be negative so it equals 0

we want x by itself for x+12=0
so we subtract both sides by 12

omg I am facepalming over this.

there are two solutions of x.

we got x = 0 for 5x=0
now solve
x+12 = 0
by subtracting 12 on both sides.

Its 11pm I have had a long day I am already bad at math add me doing this half asleep.....

I DID!

0-12?

X+12=0
x+12-12=0-12

GOD ITS LIKE 6th grade ALGEBRA! 12 minus zero is 12

Zero minus twelve not twelve minus zero

Well Negative 12

thank you @taramgrant0543664

But it is still 12

Just on the left side XD

Zero minus twelve is negative twelve

I just said that ._.

5x(x+12) = 0
5x = 0
divide 5 on both sides and we have x = 0
x+12 = 0
-12 -12
x = -12

It's not twelve it's negative twelve

lol ok

meow ^.^

Oh and I got an 89% in the test! XD

So double thanks now good night and bye