A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
I need help on simplifying radicals, so could someone explain to me how to solve this? 2√16a^4b^2
anonymous
 one year ago
I need help on simplifying radicals, so could someone explain to me how to solve this? 2√16a^4b^2

This Question is Closed

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[2\sqrt{16a^4b^2}\]?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1So since it's being multiplied you can split it all up as such \[2\sqrt{16}\sqrt{a^4}\sqrt{b^2}\] can you simplify from there?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How would you simplify from 16? Because don't you need one number that is a perfect square and the other one not? The only thing I can think of is 4x4 but they're both perfect squares...

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[\sqrt{x} = x^{1/2}\] \[\sqrt{a^4}=(a^4)^{1/2}=a^{4/2}=a^{2}\] do the same with \[\sqrt{b^2}\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Also remember \[4^2 = 16\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, so would it be \[8\sqrt{a ^{2}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Because the "b" cancels out because it's b squared?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1No, look at what I wrote above, \[\sqrt{x} = x^{1/2}\] this is the same thing, just exponent. \[\sqrt{b^2} = (b^2)^{1/2} \] and for your other question \[\sqrt{16} = \sqrt{4 \times 4} = \sqrt{4}\sqrt{4} = 2 \times 2 = 4\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I am a moron when it comes to math, so bear with me. Soooo sorry. :/

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So it would just be b? Gosh, exponents really confuse me.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yup perfect! Here is a little guide that a user iambatman made for exponents, it may help clear some things up dw:1439179339225:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[8b \sqrt{a ^{2}}\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Not quite, \[8a^2b\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Remember it was \[\sqrt{a^4}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So the a goes on the other side of the radical when simplified?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1I don't quite follow

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Oh, there is no point to put square root sign, a^2 is simplied

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It goes outside of the radical/square root when it got simplified from \[a^{4} \to a ^{2}\]?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge \sqrt{a^4}=(a^4)^{1/2}=a^{4/2}=a^{2}\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Does that make sense?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes, it does. I understand now. Thank you so much! I had a horrible teacher when I took Algebra.. I practically had to teach myself everything, so I struggle a lot. Thanks again!

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1When we struggle we learn! And your welcome :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.