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\[2\sqrt{16a^4b^2}\]?

Yes.

\[\sqrt{16}=4\]

\[\sqrt{x} = x^{1/2}\]
\[\sqrt{a^4}=(a^4)^{1/2}=a^{4/2}=a^{2}\] do the same with \[\sqrt{b^2}\]

Also remember \[4^2 = 16\]

Okay, so would it be \[8\sqrt{a ^{2}}\]

Because the "b" cancels out because it's b squared?

I am a moron when it comes to math, so bear with me. Soooo sorry. :/

It's ok :P

So it would just be b? Gosh, exponents really confuse me.

\[8b \sqrt{a ^{2}}\]

would it be this?

Not quite, \[8a^2b\]

Remember it was \[\sqrt{a^4}\]

So the a goes on the other side of the radical when simplified?

I don't quite follow

Oh, there is no point to put square root sign, a^2 is simplied

It goes outside of the radical/square root when it got simplified from \[a^{4} \to a ^{2}\]?

\[\huge \sqrt{a^4}=(a^4)^{1/2}=a^{4/2}=a^{2}\]

Does that make sense?

When we struggle we learn! And your welcome :)