find a_18 when a_1=27, d=-6

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find a_18 when a_1=27, d=-6

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Using an arithmetic sequence that follows the formula: \(a_n =a_1 +(n-1)d\)
-75 is my answer
\[\large a_{\color{red}{n}} = a_{\color{red}{18}}\] Therefore we can conclude \(n=18\). Let's see..

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That is correct :)
thank you, but i did it the long way, d=-6 a_1=27 a_n=?
Perhaps you can show me how you've solved it?
i did 27-6=21 21-6=15 15-6=9 and so on until i got to a18.
but what is a_n?
That's also a good way to go about finding it.
it cant be 27(18-1)-6.
And why do you think it cant be?
because i got 453
and -2754 if i do the negative sign, first answer (453) i did a minus sign
This is how I solved it.\[a_n = a_{18} \longrightarrow n=18\]\[a_n=27+(18-1)(-6)\]\[a_n=27 -102\]\[a_n=-75\]
thats why, i forgot the addition sign.
:)
thank you ma'am!
No problem and good luck!

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