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anonymous
 one year ago
SOMEONE PLEASE HELP ME WITH THIS ALGEBRA 2 . its hard and im really stressed
anonymous
 one year ago
SOMEONE PLEASE HELP ME WITH THIS ALGEBRA 2 . its hard and im really stressed

This Question is Closed

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0Well, whats the question? :D

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Match the complex expression to its correct simplified form. 1. i^22 2. i&7 3. 5 + 8i  4 + 2i 4. (2  3i)(3 + 5i) 5. (2  i)(2 + i)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1hmm... well for the first one , we know that \[i^2= 1 \] so we can split the \[i^{22} \] with the exponent rule but that can take long... wow @Astrophysics so fast lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol . i just dont understand it period

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1well I know why it was done fast.. the exponent was an even number XD it's like writing i^2 11 times

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Main thing is you understand that i^2 = 1

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Which can be proved from \[i^2 = (0+i)^2 \implies (0+i)(0+i) \implies ...1+0i = 1\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1long way... not recommended lol \[(i^2)(i^2)(i^2)(i^2)(i^2)(i^2)(i^2)(i^2)(i^2)(i^2)(i^2)\] \[(1)(1)(1)(1)(1)(1)(1)(1)(1)(1)(1)\] \[(1)(1)(1)(1)(1)(1) \rightarrow (1)(1)= 1 \]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1i^{100} is gonna hurt by hand XD

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1so next question For 3. 5 + 8i  4 + 2i we can combine like terms so our answer is in the form of ai+b or a+bi

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[i^7 \implies (i^2)(i^2)(i^2)i\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so number 2 would be i^7 (1)(1)(1)(1)(1)(1)(1) = 1

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Naw, \[i = \sqrt{1}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1oh I read that second problem wrong. I thought it was i and 7 XD

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[i^7 = i^6 i = 1 \times i = i\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so problem 3 would be i^3 ?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1problem 3 has 3. 5 + 8i  4 + 2i we can combine like terms so our answer is in the form of ai+b or a+bi

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yeah just combine like terms haha

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1close but should be +1

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1we can rearrange it to make it a bit easier 54+8i+2i > 1+10i

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1well the attempt wasn't that bad.... just 54=1

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1the last 2 problems is just using FOIL and using the fact that\[ i^2 = 1 \] again the final form of these questions is a+bi or ai+b

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(2  i)(2 + i) 4 + 2i  2i  i^2 4+i^2

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[(2i)(2+i) \implies (2)(2)+2i+(2)(i)i^2 \implies 4+2i2ii^2 = 4i^2 = 4(1) = 4+1 = 5\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[4i^2 = 4(1) \implies 4+1 = 5\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1(2i)(2+i) 4+2i2ii^2 4i^2 since i^2 = 1 4(1) = 4+1 = 5

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Sorry it got cut off there

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1You're on the right path though, just a sign error :)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1it was a good attempt though .. just when we see i^2, we need to use substitution Replace i^2 with 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(2  3i)(3 + 5i) 6 + 10i  9i  15i 6  14i

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1(23i)(3+5i) 6+10i9i15i^2

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1remember... i^2 = 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how do you apply 15 and i^2

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[(23i)(3+5i) = 6+10i9i15i^2 \implies 6+i15i^2\] \[6+i15(1) \implies 6+i+15 \implies 21 +i\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Do you see your error now?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1i^2 = 1 replace the i^2 with 1 6+10i9i15i^2 since i^2 = 1 6+10i9i15(1)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge \checkmark\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0omg thank yall . !!!!!! can you help me with something else ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01. X^2 + 9 = 0 2. 3x^2 + 11 = 181

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1are these questions solve for x?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1You can set x^2 = 9 this has to do with imaginary numbers as well

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Solve the following: x^2 + 9 = 0 Select one: a. 2 + 4i b. + 3i c. not possible d. + 9i

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Remember as I mentioned before \[i = \sqrt{1}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Solve: 3x^2 + 11 = 181 Select one: a. not possible b. + 8i c. 1 + 13i d. + 4i

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[x^2 =  9\] what do you get

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1ah yes once we square root both sides on x^2=9 we're gonna have an imaginary case. since negative signs in radicals aren't allowed, the result is imaginary.. denoted by i

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1That's one solution remember when we take a square root we get a positive and negative value :)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1hmm I guess for this multiple choice, it's only considering the positive version when taking the square root dw:1439181642696:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so positive and negative 3i

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1So here is what's going on really

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[x^2 = 9 \implies x = \pm \sqrt{9} \implies \pm \sqrt{1} \sqrt{9} \implies \pm 3i\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the next one is positive or negative 8i

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1We just factor out the \[\sqrt{1}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.13x^2 +11=181 3x^2 = 18111 3x^2=192 x^2 = 64 X = \sqrt{64} x = 8i, 8i

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(2x^28x +10=0) im going to go this one tell me if its correct

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439181899563:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im not sure what to do next

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Why would you do that, just factor

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1I wouldn't do that at all

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1or complete the square i guess

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.12x^28x+10=0 all of these numbers are even .. .they have one even number in common

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Here lets make it easier on you \[2(x^24x+5)=0\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Oh sorry Usuki xD

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.12 x 1 = 2 2 x 4 = 8 2 x 5 = 10 all of them have 2 in common . so yank that out and we should have 2(x^24x+5) = 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then factor x^2  4x + 5 ?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1then factor (x^24x+5) since 5 is a prime number the only combination is 1 x 5 = 5 we need a negative number to produce 4 so 1 5 = 4 (x+1)(x5) ... only that produces a different sign patern but I'm wondering if this is written right. by discriminant formula (4)^24(1)(5) = 1620 = 4 oh great we need quadratics _! .. complex roots.. mhm

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ b \pm \sqrt{b^24ac}}{2a}\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Quadratic is the easiest way to approach this

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1since a = 1, b = 4, and c = 5 but we got our b^24ac

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1You'll have two complex solutions

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ 4 \pm \sqrt{4}}{2}\] \[\frac{ 4 \pm \sqrt{4}i}{2}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1take the square root of 4 and then reduce these fractions.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ 4 \pm 2i}{2} \rightarrow 2 \pm i\] correct :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have other work to complete if I need help will you all be on ?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1depends on the time zone... I'm a bit worn out from last night.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Just open a new question, and someone will get to it eventually :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok thanks for yall help & eastern
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