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anonymous

  • one year ago

What is the solution of log2x + 3125 = 3? a. x = 1 over 3 b. x = 1 c. x = 7 over 3 d. x = 4

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  1. anonymous
    • one year ago
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    hey

  2. anonymous
    • one year ago
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    hi there! i was just about to tag you.

  3. Nnesha
    • one year ago
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    \[\huge\rm log_2 x +3125 =3\] first) move the 3125 to the right side 2nd) convert log to exponential form

  4. anonymous
    • one year ago
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    thats right. do you know how to convert to exponential form?

  5. anonymous
    • one year ago
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    \[\log_{2}x = -3122 \]

  6. anonymous
    • one year ago
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    okay, i'm on the right track

  7. Nnesha
    • one year ago
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    |dw:1439212156992:dw|

  8. Nnesha
    • one year ago
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    let us know what you get!

  9. anonymous
    • one year ago
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    so we get 2^-3122 = x

  10. Nnesha
    • one year ago
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    let her try it first :=)

  11. anonymous
    • one year ago
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    @badsuns are you getting this? I know I didn't realize she hadn't I thought you replying was her lol sorry.

  12. Nnesha
    • one year ago
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    it's okay.

  13. anonymous
    • one year ago
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    okay let me try to solve it

  14. anonymous
    • one year ago
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    wait, this is totally wrong because i was not clear when writing the question. the log is 2x + 3.

  15. anonymous
    • one year ago
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    so so sorry about that!

  16. Nnesha
    • one year ago
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    \[\huge\rm log_2 (2x+3) =3\] like ths ?

  17. anonymous
    • one year ago
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    ouch ok. So is it like this?\[\log_{2x+3}125 \]

  18. anonymous
    • one year ago
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    yes :)

  19. anonymous
    • one year ago
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    which one lol

  20. anonymous
    • one year ago
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    @twistnflip wrote the equation correctly.

  21. anonymous
    • one year ago
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    i didn't see @Nnesha's reply until i scrolled up, sorry about that.

  22. anonymous
    • one year ago
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    ok. so thats why none of your answer choices matched my answer lol

  23. anonymous
    • one year ago
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    really sorry about that again

  24. Nnesha
    • one year ago
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    \[\log_{2x+3} 125 =3 \] like this ?

  25. anonymous
    • one year ago
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    yes

  26. Nnesha
    • one year ago
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    alright so now first step is to convert log to exponential form base is 2x+3

  27. anonymous
    • one year ago
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    right. remember how to do that?

  28. anonymous
    • one year ago
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    so it would be (2x+3)^(3) = 125 ?

  29. Nnesha
    • one year ago
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    perfect!!

  30. Nnesha
    • one year ago
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    now take cube root both sides to cancel out cube

  31. anonymous
    • one year ago
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    yes thats awesome. now do you know how to take cube roots?

  32. Nnesha
    • one year ago
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    \[\sqrt[3]{(2x+3)^3}=\sqrt[3]{125}\] solve for x

  33. anonymous
    • one year ago
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    okay, let me try that out.

  34. anonymous
    • one year ago
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    what do you get?

  35. anonymous
    • one year ago
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    you should get: 2x+3 = 5 -3 -3 2x = 2 x = 1

  36. Nnesha
    • one year ago
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    sigh.

  37. Nnesha
    • one year ago
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    lol

  38. anonymous
    • one year ago
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    Answer choice B. What lol she was taking way too long

  39. anonymous
    • one year ago
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    Just wanted to make sure she wasn't stuck

  40. Nnesha
    • one year ago
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    it's okay we should give them a few mints

  41. anonymous
    • one year ago
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    ugh sorry my internet is acting up, i had to reset it. let me try and see i got the answer by doing it correctly.

  42. anonymous
    • one year ago
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    no, i keep doing something wrong, not even sure what.

  43. anonymous
    • one year ago
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    waaaaait, i know what i did. i got it now.

  44. Nnesha
    • one year ago
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    nice.

  45. anonymous
    • one year ago
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    Awesome!! Let me know if you need anything... Medal?

  46. anonymous
    • one year ago
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    I will give Nnesha one if you give me one

  47. anonymous
    • one year ago
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    thank you guys so so much. it's hard for me to remember how to do this since i haven't been in an actual class for about two months. thanks for your patience and help.

  48. Nnesha
    • one year ago
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    i'm okay without medal. so no big deal.

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