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hey

hi there! i was just about to tag you.

thats right. do you know how to convert to exponential form?

\[\log_{2}x = -3122 \]

okay, i'm on the right track

|dw:1439212156992:dw|

let us know what you get!

so we get 2^-3122 = x

let her try it first :=)

it's okay.

okay let me try to solve it

wait, this is totally wrong because i was not clear when writing the question. the log is 2x + 3.

so so sorry about that!

\[\huge\rm log_2 (2x+3) =3\]
like ths ?

ouch ok. So is it like this?\[\log_{2x+3}125 \]

yes :)

which one lol

@twistnflip wrote the equation correctly.

ok. so thats why none of your answer choices matched my answer lol

really sorry about that again

\[\log_{2x+3} 125 =3 \] like this ?

yes

alright so now first step is to convert log to exponential form
base is 2x+3

right. remember how to do that?

so it would be (2x+3)^(3) = 125 ?

perfect!!

now take cube root both sides to cancel out cube

yes thats awesome. now do you know how to take cube roots?

\[\sqrt[3]{(2x+3)^3}=\sqrt[3]{125}\] solve for x

okay, let me try that out.

what do you get?

you should get:
2x+3 = 5
-3 -3
2x = 2
x = 1

sigh.

lol

Answer choice B. What lol she was taking way too long

Just wanted to make sure she wasn't stuck

it's okay we should give them a few mints

no, i keep doing something wrong, not even sure what.

waaaaait, i know what i did. i got it now.

nice.

Awesome!! Let me know if you need anything... Medal?

I will give Nnesha one if you give me one

i'm okay without medal.
so no big deal.