What is the solution of log2x + 3125 = 3? a. x = 1 over 3 b. x = 1 c. x = 7 over 3 d. x = 4

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What is the solution of log2x + 3125 = 3? a. x = 1 over 3 b. x = 1 c. x = 7 over 3 d. x = 4

Mathematics
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hey
hi there! i was just about to tag you.
\[\huge\rm log_2 x +3125 =3\] first) move the 3125 to the right side 2nd) convert log to exponential form

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Other answers:

thats right. do you know how to convert to exponential form?
\[\log_{2}x = -3122 \]
okay, i'm on the right track
|dw:1439212156992:dw|
let us know what you get!
so we get 2^-3122 = x
let her try it first :=)
@badsuns are you getting this? I know I didn't realize she hadn't I thought you replying was her lol sorry.
it's okay.
okay let me try to solve it
wait, this is totally wrong because i was not clear when writing the question. the log is 2x + 3.
so so sorry about that!
\[\huge\rm log_2 (2x+3) =3\] like ths ?
ouch ok. So is it like this?\[\log_{2x+3}125 \]
yes :)
which one lol
@twistnflip wrote the equation correctly.
i didn't see @Nnesha's reply until i scrolled up, sorry about that.
ok. so thats why none of your answer choices matched my answer lol
really sorry about that again
\[\log_{2x+3} 125 =3 \] like this ?
yes
alright so now first step is to convert log to exponential form base is 2x+3
right. remember how to do that?
so it would be (2x+3)^(3) = 125 ?
perfect!!
now take cube root both sides to cancel out cube
yes thats awesome. now do you know how to take cube roots?
\[\sqrt[3]{(2x+3)^3}=\sqrt[3]{125}\] solve for x
okay, let me try that out.
what do you get?
you should get: 2x+3 = 5 -3 -3 2x = 2 x = 1
sigh.
lol
Answer choice B. What lol she was taking way too long
Just wanted to make sure she wasn't stuck
it's okay we should give them a few mints
ugh sorry my internet is acting up, i had to reset it. let me try and see i got the answer by doing it correctly.
no, i keep doing something wrong, not even sure what.
waaaaait, i know what i did. i got it now.
nice.
Awesome!! Let me know if you need anything... Medal?
I will give Nnesha one if you give me one
thank you guys so so much. it's hard for me to remember how to do this since i haven't been in an actual class for about two months. thanks for your patience and help.
i'm okay without medal. so no big deal.

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