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mathmath333
 one year ago
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mathmath333
 one year ago
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mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0\(\large \color{black}{\begin{align} &\normalsize \text{What is the arithmatic mean of first}\ n \ \text{natural numbers} \hspace{.33em}\\~\\ & a.)\ 2(n+1) \hspace{.33em}\\~\\ & b.)\ \dfrac{n(n+1)}{2} \hspace{.33em}\\~\\ & c.)\ \dfrac{(n+1)}{2} \hspace{.33em}\\~\\ & d.)\ \dfrac{n^{2}(n+1)}{2} \hspace{.33em}\\~\\ \end{align}}\)

OregonDuck
 one year ago
Best ResponseYou've already chosen the best response.0What is your question I can not see it????!?

phi
 one year ago
Best ResponseYou've already chosen the best response.3the sum of the first n numbers 1+2+3+..+n = n(n+1)/2 the average is found by dividing that by n
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