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anonymous
 one year ago
What function is graphed below? (graph attached in comments)
f(x) = log (x − 3)
f(x) = log (x + 3)
f(x) = log x + 3
f(x) = log x − 3
anonymous
 one year ago
What function is graphed below? (graph attached in comments) f(x) = log (x − 3) f(x) = log (x + 3) f(x) = log x + 3 f(x) = log x − 3

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright @phi is awesome he will help...

phi
 one year ago
Best ResponseYou've already chosen the best response.0the key number is what is log(1) ? if you don't know, what does your calculator say?

phi
 one year ago
Best ResponseYou've already chosen the best response.0logs are confusing (for me, anyway) but log(1) means what exponent gives us 1? (we assume base 10) 10 to what power is 1? the factoid to remember is 10^0 = 1 the power is 0 log(1) means what power gives us 1. and the power is 0 log(1)=0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ah sorry, didn't get a notification that you replied.

phi
 one year ago
Best ResponseYou've already chosen the best response.0assuming you know log(1)=0 we look for the x value of the graph where it crosses the xaxis (i.e. where y is zero) what x value is that ?

phi
 one year ago
Best ResponseYou've already chosen the best response.0you have to look at the graph. put you finger on the xaxis and move your finger along the xaxis until you reach the curve. then read what x value you are at . can you do that ?

phi
 one year ago
Best ResponseYou've already chosen the best response.0now we have to figure out how to change log(x) so that it is translated (slid over) from x=1 to x= 2 (because it should be at 0 at x=1, but we see it was moved so that it is at 0 when x=2)

phi
 one year ago
Best ResponseYou've already chosen the best response.0the "fast way" is to memorize: to slide a function f(x) to the *left* n steps, write f(x+n) to slide the function f(x) to the *right* n steps, write f(xn)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i figured it out :) thanks!
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