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anonymous
 one year ago
Needed a check on Algebra 2 graphing!
Describe the graph of the function f(x) = x3 − 15x2 + 68x − 96. Include the yintercept, xintercepts, and the end behavior.
and my answer is:
First, to find the y intercept, 0 must be substituted in f(x) to be f(0). Then the equation must be solved. f(0) = (0)^315(0)^2+68(0)96 . It equals 96. This means that the y intercept must be (0,96) . The x intercepts can be solved for, there are three of them, as show by the graph. The three x intercepts are 3, 4, and 8 . The end behavior is f(x)>+∞ as x>+∞ and the left side is f(x)>∞ as x>∞ .
anonymous
 one year ago
Needed a check on Algebra 2 graphing! Describe the graph of the function f(x) = x3 − 15x2 + 68x − 96. Include the yintercept, xintercepts, and the end behavior. and my answer is: First, to find the y intercept, 0 must be substituted in f(x) to be f(0). Then the equation must be solved. f(0) = (0)^315(0)^2+68(0)96 . It equals 96. This means that the y intercept must be (0,96) . The x intercepts can be solved for, there are three of them, as show by the graph. The three x intercepts are 3, 4, and 8 . The end behavior is f(x)>+∞ as x>+∞ and the left side is f(x)>∞ as x>∞ .

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anonymous
 one year ago
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