A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

vera_ewing

  • one year ago

.

  • This Question is Closed
  1. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    pick a number for x

  2. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    let x=1 or x= 0 now replace x by 1

  3. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    \[y=3^1+1\] y=4 so look at the graph when x=1 y should be equal to 4

  4. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    hmm nope

  5. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1439219878431:dw| when x=1 y isn't equal to 4 so no not D

  6. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    oops

  7. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1439219923624:dw|

  8. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    oky look at the graph when x=1 y = what ?

  9. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1439220002101:dw|

  10. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1439220021987:dw| when x=1 is the graph of the equation passes through the that blue dot ?

  11. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    no...

  12. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1439220125439:dw|

  13. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    lol

  14. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    jk i just reread the post why did you choose C first ?

  15. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    look at the graph when x=1 y =4 ??

  16. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1439220262087:dw|

  17. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1439220308084:dw|

  18. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    you can pick any number for x let x=0\[f(x) =3^0 +1 \] anything to the zero power is one so f(X)=1+1 =2

  19. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1439220460540:dw|

  20. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    yes

  21. TheSmartOne
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    why are all the comments deleting? ._.

  22. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    o.O

  23. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.