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what is the equation? \(2^y = 3~~or 2^y =x??\)
That is \(log_2 3 =y\) and its graph is a line.
Can't be one of the options.
If the question is \(2^y =x \\y = log_2 x\) then, we can consider it is a function of x. But your equation is y = a number, not a function. Therefore, if it has a graph, the graph must be a horizontal straight line, not a curve as shown.
Or!! my knowledge is not enough to solve. I am sorry. Let's wait for @ganeshie8
The given graph must be a graph of \(f(x) = \log_2 x\) so that you can check its value at \(x=3\) and thus find \(y\), as Loser66 said. What properties of the \(\log_2 x\) can you think about that can help us eliminate the wrong choices? I'll start: it is not defined at \(x=0\), so it never crosses the line \(x=0\) (which is what you may know as the y-axis).
Why can't it be B or C?
They never really cross the line \(x=0\)... they're only moving along it. The curve will get reaaaaaaaally close to \(x=0\) but never will it touch it.
Why not A or B or D?
I'm not convinced.
Did she mention why it's C?
Do you know who to evaluate \(f(x) = \log_2 x \) at different points? Basically do you know how the log function works?
Have you been taught about graphing functions?
And do you know about the logarithmic function?
Well, if for instance, I ask you what \(\log(1)\) is... what is it?
Why did you choose C?
Well, why did you choose A?
You shouldn't do that. For instance, the graph given in A crosses the y-axis.
C is correct simply because it is the graph of \(f(x) = \log_2 x \).
That's what I thought, but you didn't confirm!
you want to chooses the graph that plots log base 2(x) you should look for the graph that goes through y=0 when x=1 and y=1 when x=2
and y=2 when x= 4
You know that \(2^y = 3\) so \(y = \log_2 3\). Now you can graph \(f(x) = \log_2 x\) and find the value of \(f(x)\) at \(x = 3\).