Cade throws a baseball from a starting height of 6 feet, with an initial velocity of 22 feet per second. Which of the following equations shows the path of the baseball? H(t) = −16t^2 + 6t + 22 H(t) = −16t^2 + 22t + 6 H(t) = −16t^2 + 28t H(t) = −16t^2 + 28

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Cade throws a baseball from a starting height of 6 feet, with an initial velocity of 22 feet per second. Which of the following equations shows the path of the baseball? H(t) = −16t^2 + 6t + 22 H(t) = −16t^2 + 22t + 6 H(t) = −16t^2 + 28t H(t) = −16t^2 + 28

Mathematics
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oh this is easy. H(0) must be 6
I'm not sure tbh, I'm not very good with all this. Could you explain it to me?
yes

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I am assuming 't' is the time and H(t) is the height of the ball for a given 't'. So it says that the ball starts its motion from 6 feet of height .
doesn't matter what the velocity is
it is clear that initial height is 6
start means t=0
just put 0 for t, and one takes 6 is the answer:)
but which of the choices is the answer? because you say six is the answer but it's not clear to me
ah yes. So think about 2nd one
if put 0 for each 't' , it is something like H(0) = -16(0)^2 +22(0) + 6
solve it. will get 6
OHHHHHHH okay
I uderstand it now xD
bye
Thanks for the help ^.^
my pleasure :)

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