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lalaland_lauren
 one year ago
Cade throws a baseball from a starting height of 6 feet, with an initial velocity of 22 feet per second. Which of the following equations shows the path of the baseball?
H(t) = −16t^2 + 6t + 22
H(t) = −16t^2 + 22t + 6
H(t) = −16t^2 + 28t
H(t) = −16t^2 + 28
lalaland_lauren
 one year ago
Cade throws a baseball from a starting height of 6 feet, with an initial velocity of 22 feet per second. Which of the following equations shows the path of the baseball? H(t) = −16t^2 + 6t + 22 H(t) = −16t^2 + 22t + 6 H(t) = −16t^2 + 28t H(t) = −16t^2 + 28

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lochana
 one year ago
Best ResponseYou've already chosen the best response.2oh this is easy. H(0) must be 6

lalaland_lauren
 one year ago
Best ResponseYou've already chosen the best response.0I'm not sure tbh, I'm not very good with all this. Could you explain it to me?

lochana
 one year ago
Best ResponseYou've already chosen the best response.2I am assuming 't' is the time and H(t) is the height of the ball for a given 't'. So it says that the ball starts its motion from 6 feet of height .

lochana
 one year ago
Best ResponseYou've already chosen the best response.2doesn't matter what the velocity is

lochana
 one year ago
Best ResponseYou've already chosen the best response.2it is clear that initial height is 6

lochana
 one year ago
Best ResponseYou've already chosen the best response.2just put 0 for t, and one takes 6 is the answer:)

lalaland_lauren
 one year ago
Best ResponseYou've already chosen the best response.0but which of the choices is the answer? because you say six is the answer but it's not clear to me

lochana
 one year ago
Best ResponseYou've already chosen the best response.2ah yes. So think about 2nd one

lochana
 one year ago
Best ResponseYou've already chosen the best response.2if put 0 for each 't' , it is something like H(0) = 16(0)^2 +22(0) + 6

lalaland_lauren
 one year ago
Best ResponseYou've already chosen the best response.0I uderstand it now xD

lalaland_lauren
 one year ago
Best ResponseYou've already chosen the best response.0Thanks for the help ^.^
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