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lalaland_lauren

  • one year ago

Cade throws a baseball from a starting height of 6 feet, with an initial velocity of 22 feet per second. Which of the following equations shows the path of the baseball? H(t) = −16t^2 + 6t + 22 H(t) = −16t^2 + 22t + 6 H(t) = −16t^2 + 28t H(t) = −16t^2 + 28

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  1. lochana
    • one year ago
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    oh this is easy. H(0) must be 6

  2. lalaland_lauren
    • one year ago
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    I'm not sure tbh, I'm not very good with all this. Could you explain it to me?

  3. lochana
    • one year ago
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    yes

  4. lochana
    • one year ago
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    I am assuming 't' is the time and H(t) is the height of the ball for a given 't'. So it says that the ball starts its motion from 6 feet of height .

  5. lochana
    • one year ago
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    doesn't matter what the velocity is

  6. lochana
    • one year ago
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    it is clear that initial height is 6

  7. lochana
    • one year ago
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    start means t=0

  8. lochana
    • one year ago
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    just put 0 for t, and one takes 6 is the answer:)

  9. lalaland_lauren
    • one year ago
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    but which of the choices is the answer? because you say six is the answer but it's not clear to me

  10. lochana
    • one year ago
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    ah yes. So think about 2nd one

  11. lochana
    • one year ago
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    if put 0 for each 't' , it is something like H(0) = -16(0)^2 +22(0) + 6

  12. lochana
    • one year ago
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    solve it. will get 6

  13. lalaland_lauren
    • one year ago
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    OHHHHHHH okay

  14. lalaland_lauren
    • one year ago
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    I uderstand it now xD

  15. lochana
    • one year ago
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    bye

  16. lalaland_lauren
    • one year ago
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    Thanks for the help ^.^

  17. lochana
    • one year ago
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    my pleasure :)

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