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anonymous

  • one year ago

A bag has 4 green pencils and 8 blue pencils. If someone reaches into the bag and randomly removes 2 pencils, what is the probability that both are not green ?PLZ HELP !!!

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  1. anonymous
    • one year ago
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    P is(1- (8/12))*(1-(7/11))

  2. anonymous
    • one year ago
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    I dont understand nick123457

  3. anonymous
    • one year ago
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    @nick1234567

  4. anonymous
    • one year ago
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    because pro of not happing is 1-prob and then fill in the prob= P(blue penci) for both times

  5. anonymous
    • one year ago
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    does that help?

  6. anonymous
    • one year ago
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    No

  7. anonymous
    • one year ago
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    okay well the prob of getting a blue pencil is 8/12 correct?

  8. anonymous
    • one year ago
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    There are 12 pencils in total should I subtract 2 ?

  9. anonymous
    • one year ago
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    what are the options?

  10. anonymous
    • one year ago
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    Yeah the probability of getting a blue is 8/12

  11. anonymous
    • one year ago
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    What should I do now ? @nick1234567

  12. anonymous
    • one year ago
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    so for the first pencil the prob of not getting green is (8/12) correct?

  13. anonymous
    • one year ago
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    Yeah

  14. anonymous
    • one year ago
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    so take that * the prob of not getting blue or getting green (same thing) the next time which is 7/11

  15. anonymous
    • one year ago
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    so 8/12 * 7/11 =answer

  16. anonymous
    • one year ago
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    Kk thank u so much I really appreciate it :) @ nick1234567

  17. anonymous
    • one year ago
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    anytime glad i could help!!!

  18. anonymous
    • one year ago
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    @nick1234567 I multiped it & got 56/132

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