anonymous
  • anonymous
A bag has 4 green pencils and 8 blue pencils. If someone reaches into the bag and randomly removes 2 pencils, what is the probability that both are not green ?PLZ HELP !!!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
P is(1- (8/12))*(1-(7/11))
anonymous
  • anonymous
I dont understand nick123457
anonymous
  • anonymous
@nick1234567

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anonymous
  • anonymous
because pro of not happing is 1-prob and then fill in the prob= P(blue penci) for both times
anonymous
  • anonymous
does that help?
anonymous
  • anonymous
No
anonymous
  • anonymous
okay well the prob of getting a blue pencil is 8/12 correct?
anonymous
  • anonymous
There are 12 pencils in total should I subtract 2 ?
anonymous
  • anonymous
what are the options?
anonymous
  • anonymous
Yeah the probability of getting a blue is 8/12
anonymous
  • anonymous
What should I do now ? @nick1234567
anonymous
  • anonymous
so for the first pencil the prob of not getting green is (8/12) correct?
anonymous
  • anonymous
Yeah
anonymous
  • anonymous
so take that * the prob of not getting blue or getting green (same thing) the next time which is 7/11
anonymous
  • anonymous
so 8/12 * 7/11 =answer
anonymous
  • anonymous
Kk thank u so much I really appreciate it :) @ nick1234567
anonymous
  • anonymous
anytime glad i could help!!!
anonymous
  • anonymous
@nick1234567 I multiped it & got 56/132

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