anonymous
  • anonymous
Given the parent functions f(x) = log10 x and g(x) = 5x − 2, what is f(x) • g(x)?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@Astrophysics
Astrophysics
  • Astrophysics
\[f(x)g(x) = \log_{10}x (5x-2)\]
Astrophysics
  • Astrophysics
You're just multiplying the functions

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More answers

anonymous
  • anonymous
Thanks! Can I ask one more?
anonymous
  • anonymous
If f(x) = log2 (x + 4), what is f−1(3)?
Astrophysics
  • Astrophysics
The \[f^{-1}\] represents inverse
anonymous
  • anonymous
yes:)
Astrophysics
  • Astrophysics
To find the inverse: Replace f(x) with y Switch x's and y's, so put x where y is and x where y is. Solve for y Replace y with f^-1(x)
Astrophysics
  • Astrophysics
Once you find the inverse just plug in 3 into the function and evaluate :-)
anonymous
  • anonymous
y=log2(x+4)
Astrophysics
  • Astrophysics
good keep going
anonymous
  • anonymous
x=log2(y+4)
Astrophysics
  • Astrophysics
right
anonymous
  • anonymous
im confused on how to solve for "Y"
Astrophysics
  • Astrophysics
Since it's \[\log_2\] as the base we will have to take the power of 2 to on both sides so the following \[\huge 2^x = 2^{\log_2(y+4)} \implies 2^x = y+4\]
anonymous
  • anonymous
hmm then wouldnt we have to get y alone?
anonymous
  • anonymous
Would the answer be 8?
Loser66
  • Loser66
f(a) =b , hence \(f^{-1} (b) =a\) ok?
Loser66
  • Loser66
we need find \(f^{-1} (3) \) of \(f(x) = log 2(x+4)\), right? That is just let log 2(x+4) =3, and solve for x.
Astrophysics
  • Astrophysics
You can do either way you should get same result
anonymous
  • anonymous
2?
Astrophysics
  • Astrophysics
No, \[y=2^x-4 \implies f^{-1}(x) = 2^x-4 \implies f^{-1}(3) = 2^3-4\]
anonymous
  • anonymous
oh! okay so then I got, 4
Loser66
  • Loser66
confirm: \(log (2(x+4))\) or (x+4)*log 2??
Astrophysics
  • Astrophysics
Yes, 4 sounds betters :)
anonymous
  • anonymous
2x2x2=4x2=8 8-4=4 :)
Astrophysics
  • Astrophysics
I think the original question was \[\log_2(x+4)\] right?
anonymous
  • anonymous
yes
Astrophysics
  • Astrophysics
Ok we're good then
Astrophysics
  • Astrophysics
Thanks @Loser66
anonymous
  • anonymous
yay! Thanks guysss:)
Loser66
  • Loser66
ok, clear.

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