anonymous
  • anonymous
A jar contains 18 apple lollipops, 7 strawberry lollipops, and 10 grape lollipops. Irvin randomly selects a lollipop, gives it to his brother, and then randomly selects another lollipop for himself. What is the probability that Irvin selected a grape lollipop for his brother and an apple lollipop for himself? Write your answer as a percent. Round to the nearest tenth of a percent.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
First choice is "1 of 10 grape lollipops from 35 lollipops" The probablity is 10/35 = 2/7 Second choice is "1 of 18 apple lollipops from 34 lollipops" So probablity is 18/34 = 9/17 Between this is AND so you have to these probablities multiply: P(A) = 2/7 * 9/17 = 18/119 P(A) = 18/119 * 100% = 1800/119 % It is approximaly 15,1 %. Is this right
anonymous
  • anonymous
probability of getting a grape lollipop:10/35 probability of getting an apple lollipop after grape lollipop has been picked : 18/34 Do 10/35*18/34
anonymous
  • anonymous
to get 18/119

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anonymous
  • anonymous
which is approximately 15%, so I'd say you are correct
anonymous
  • anonymous
Thank you

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