## purplemexican one year ago @Hero

1. Purplemexican

2. Purplemexican

its 100

3. mathstudent55

The sum of an infinite geometric series is: $$\Large S_{\infty} = \dfrac{a_1}{1 - r}$$ where $$a_1$$ is the first term, and r is the common ratio.

4. mathstudent55

We have $$a_1 = 40$$, and $$r = \dfrac{3}{5}$$ $$\Large S_{\infty} = \dfrac{a_1}{1 - r}$$ $$\Large S_{\infty} = \dfrac{40}{1 - \frac{3}{5}} = \dfrac{40}{\frac{2}{5}} = \dfrac{40\times5}{2} = 100$$

5. mathstudent55

You are correct.