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side = 2^(4/9)
area = side^2 = ?

Wait what

twice..

I got 4 to the power of 16/81

Oh ok

Now I got 2 to the power of 8/9

yes, sorry for the late reply

sure

I got one

not quite, let's take it bit by bit
f(1) = ?

Is it one

not quite
f(x) = 5^x
f(1) = ?

5 to the power of one

right
now f(0) = ?

5 to the power of zero

right, so
[f(1)-f(0)]/(1-0) = ?

Is it 1/1

no...
remember, we just calculated f(1) and f(0)
f(1) - f(0) = ?

5^1 - 5^0

right, so
[f(1)-f(0)]/(1-0) = ?

Do I have to solve the exponent

yes

5-1/ 1-0 = 4/1

right, and 4/1 = ?

right, now let's calculate the rate of change from x = 2 to x = 3
[f(3)-f(2)]/(3-2) = ?

5^3 - 5^2/ 3-2

right, keep going...

125 - 25/ 3-2

right, keep going...

100/1= 100

right

25

right so section B is 25 times as great (24 times greater) as section A

So that's the answer

yeah

Thank you