anonymous
  • anonymous
The sides of a square are 2 to the power of 4÷9 inches long. what is the area of the square?
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Vocaloid
  • Vocaloid
side = 2^(4/9) area = side^2 = ?
anonymous
  • anonymous
Wait what
anonymous
  • anonymous
How can I solve this??? @vocaloid

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More answers

Vocaloid
  • Vocaloid
it gives you the length of one side, so to find the area, you just square the length (side)*(side) = 2^(4/9) * 2^(4/9) = ?
anonymous
  • anonymous
Do I times it 4 times or just twice @vocaloid
Vocaloid
  • Vocaloid
twice..
anonymous
  • anonymous
@vocaloid
anonymous
  • anonymous
I got 4 to the power of 16/81
Vocaloid
  • Vocaloid
not quite, we have to use the exponent rule here keep the base and add the exponents together 2^(4/9) * 2^(4/9) = 2^(4/9 + 4/9) = ?
anonymous
  • anonymous
Oh ok
anonymous
  • anonymous
Now I got 2 to the power of 8/9
anonymous
  • anonymous
Is that right? @vocaloid
Vocaloid
  • Vocaloid
yes, sorry for the late reply
anonymous
  • anonymous
Do you you think you can help me with another question? @vocaloid
Vocaloid
  • Vocaloid
sure
anonymous
  • anonymous
Given the function f(x) = 5^x , section A is from = x = 0 to x = 1 and the section B is from x = 2 to x = 3. Part A: Find The average rate of change of each section Part B: How many times greater is the average rate of change of section B then section A? Explain why one rate of change is greater than the other. @vocaloid
Vocaloid
  • Vocaloid
part A) we want two values 1. the rate of change between x = 0 and x = 1 and 2. the rate of change between x = 2 and x = 3 so, let's just tackle the first part for now the rate of change between x = 0 and x = 1 can be found using the formula [f(1)-f(0)]/(1-0)
anonymous
  • anonymous
I got one
Vocaloid
  • Vocaloid
not quite, let's take it bit by bit f(1) = ?
anonymous
  • anonymous
Is it one
Vocaloid
  • Vocaloid
not quite f(x) = 5^x f(1) = ?
anonymous
  • anonymous
5 to the power of one
Vocaloid
  • Vocaloid
right now f(0) = ?
anonymous
  • anonymous
5 to the power of zero
Vocaloid
  • Vocaloid
right, so [f(1)-f(0)]/(1-0) = ?
anonymous
  • anonymous
Is it 1/1
Vocaloid
  • Vocaloid
no... remember, we just calculated f(1) and f(0) f(1) - f(0) = ?
anonymous
  • anonymous
5^1 - 5^0
Vocaloid
  • Vocaloid
right, so [f(1)-f(0)]/(1-0) = ?
anonymous
  • anonymous
Do I have to solve the exponent
Vocaloid
  • Vocaloid
yes
anonymous
  • anonymous
5-1/ 1-0 = 4/1
Vocaloid
  • Vocaloid
right, and 4/1 = ?
anonymous
  • anonymous
4
Vocaloid
  • Vocaloid
right, now let's calculate the rate of change from x = 2 to x = 3 [f(3)-f(2)]/(3-2) = ?
anonymous
  • anonymous
5^3 - 5^2/ 3-2
Vocaloid
  • Vocaloid
right, keep going...
anonymous
  • anonymous
125 - 25/ 3-2
Vocaloid
  • Vocaloid
right, keep going...
anonymous
  • anonymous
100/1= 100
Vocaloid
  • Vocaloid
right
Vocaloid
  • Vocaloid
now we're finished w/ part A part B wants us to find (rate of change from x = 2 to x = 3)/(rate of change from x = 1 to x = 2) using what we calculated earlier... 100/4 = ?
anonymous
  • anonymous
25
Vocaloid
  • Vocaloid
right so section B is 25 times as great (24 times greater) as section A
anonymous
  • anonymous
So that's the answer
Vocaloid
  • Vocaloid
as for "explain why" I would say something along the lines of "f(x) is an increasing exponential function
Vocaloid
  • Vocaloid
yeah
anonymous
  • anonymous
Thank you

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