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anonymous

  • one year ago

Write the sum using summation notation, assuming the suggested pattern continues. -4 + 5 + 14 + 23 + ... + 131

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  1. freckles
    • one year ago
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    what it is the common difference that is what are the following: 5-(-4)=? 14-5=? 23-14=?

  2. anonymous
    • one year ago
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    9 @freckles

  3. freckles
    • one year ago
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    right and we know a arithmetic sequence is of the form: \[a_n=a_1+d(n-1) \\ \text{ where } a_1 \text{ is first term } \\ \text{ and } d \text{ is common difference } \\ \text{ your answer will be of the form } \sum_{i=1}^{n} a_i=\sum_{i=1}^n [a_1+d(i-1)]\] so the only thing left to figure out is the n for which you get the last term 131

  4. freckles
    • one year ago
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    for what n is a_n =131 well just solve: \[131=a_1+d(n-1)\] where you found d to be 9

  5. anonymous
    • one year ago
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    wait so what do i do next? @freckles

  6. freckles
    • one year ago
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    did you find n yet?

  7. freckles
    • one year ago
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    for when an is 131

  8. freckles
    • one year ago
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    because that is basically the last step besides to plug into the final form

  9. anonymous
    • one year ago
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    No I didn't find it

  10. freckles
    • one year ago
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    ok well do you still need any help?

  11. freckles
    • one year ago
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    I'm not sure if that means you are having a problem solving the equation I gave you or not

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