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anonymous
 one year ago
Verify the identity. Show your work.
(1 + tan2u)(1  sin2u) = 1
my answer > cos^2x+sin^2x=1
anonymous
 one year ago
Verify the identity. Show your work. (1 + tan2u)(1  sin2u) = 1 my answer > cos^2x+sin^2x=1

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but my teacher said 6. You can rewrite each factor as another trig function squared. 1+tan^2u=(standard identity)? and 1sin^2u=(standard identity)? Once you do that, the next steps are clear. Please refer to section 5.1 of your text for examples and sample problems.

freckles
 one year ago
Best ResponseYou've already chosen the best response.3also do you mean tan^2(u) and sin^2(u) because I see tan(2u) and sin(2u)

freckles
 one year ago
Best ResponseYou've already chosen the best response.3Also are you asking us to refer to section 5.1 of your book?

freckles
 one year ago
Best ResponseYou've already chosen the best response.3I don't see how that is possible.

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0I am with @freckles It must be \((1+tan^2u)(1sin^2u) =1\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0idk yes my book 6 the number of the problem im on and idk what she means '

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0well you are right cos^2+ sin^2 =1 right ! BUT you need to prove( 1+tan^2 ) (1sin^2i) equal to 1

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge\rm (1+\tan^2u)(1\sin^2u)=1\] show that R.H.S=L.H.S are u familiar with the trig identities you have to apply that :=)

freckles
 one year ago
Best ResponseYou've already chosen the best response.3\[\cos^2(x)+\sin^2(x)=1 \\ \text{ subtract } \sin^2(x) \text{ on both sides } \\ \cos^2(x)=1\sin^2(x) \\ \text{ hint: now divide both sides of } \cos^2(x)+\sin^2(x)=1 \\ \text{ by } \cos^2(x)\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.3other than that I can't refer to any thing in your book because I don't think I have your book

freckles
 one year ago
Best ResponseYou've already chosen the best response.3but i can help you prove the identity above

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol i just need help with it i seriouly dont know what else to do

freckles
 one year ago
Best ResponseYou've already chosen the best response.3try to see if you can follow what I said above

freckles
 one year ago
Best ResponseYou've already chosen the best response.3divide both sides by cos^2(x) of the identity I spoke about just now and tell me what you have

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have sin= 1 right idk im horrible at math

freckles
 one year ago
Best ResponseYou've already chosen the best response.3Did you try to divide both sides of cos^2(x)+sin^2(x)=1 by cos^2(x)?

freckles
 one year ago
Best ResponseYou've already chosen the best response.3so do you know what cos^2(x)/cos^2(x)=? or what sin^2(x)/cos^2(x)=? or what 1/cos^2(x)=?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how did you gwt all that

freckles
 one year ago
Best ResponseYou've already chosen the best response.3Well I asked you to divide both sides of cos^2(x)+sin^2(x)=1 by cos^2(x)

freckles
 one year ago
Best ResponseYou've already chosen the best response.3\[\frac{\cos^2(x)+\sin^2(x)}{\cos^2(x)}=\frac{1}{cos^2(x)}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohhh i did it way wrong

freckles
 one year ago
Best ResponseYou've already chosen the best response.3\[\frac{\cos^2(x)}{\cos^2(x)}+\frac{\sin^2(x)}{\cos^2(x)}=\frac{1}{\cos^2(x)}\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.3cos^2(x)/cos^2(x)=1 sin^2(x)/cos^2(x)=tan^2(x) 1/cos^2(x)=sec^2(x)`

freckles
 one year ago
Best ResponseYou've already chosen the best response.3though you could just leave it as 1+tan^2(x)=1/cos^2(x) if you want

freckles
 one year ago
Best ResponseYou've already chosen the best response.3now plug in both of those results we got from the Pythagorean identity

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0\(1+tan^2u = sec^2 u =\dfrac{1}{cos^2u}\\1sin^2 u = cos^2u\\hence,(1+tan^2u)(1sin^2u)= \dfrac{1}{\cancel{cos^2u}}*\cancel{cos^2u}=1\)
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