- anonymous

cot2x + csc2x = 2csc2x - 1
my answer > cot^2+csc^4*x^3

- jamiebookeater

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- anonymous

Teacher:You cannot take terms across the = when doing a proof. You must show that the LHS=RHS. See if you can use cot^2(x)+1 = csc^2(x) to help you do this.??

- anonymous

- freckles

so those things in your problem are not double angles right?

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## More answers

- anonymous

idont thinks so
no there not

- xapproachesinfinity

looks like square not double angle
that way the left hand side is correct

- anonymous

yes

- freckles

so the problem is:
\[\cot^2(x)+\csc^2(x)=2\csc^2(x)-1\]

- anonymous

yes

- xapproachesinfinity

this problem wants you to use the id
1+cot^2=csc^2

- freckles

well let's play with this:
\[\cot^2(x)+1=\csc^2(x)\]
subtract 1 on both sides

- freckles

this will isolate the cot^2(x) term

- freckles

in then you will be able to write left hand side in terms of csc

- anonymous

umm okkk

- freckles

do this one step:
subtract 1 on both sides of
cot^2(x)+1=csc^2(x)

- anonymous

cot^2(x)csc^2 right

- freckles

what happen to the equation

- freckles

if I asked you to subtract 1 on both sides of
x+1=y
what would you get after just doing that one step

- anonymous

you would get x=y

- freckles

i'm asking you to subtract one on both sides not one side
remember whatever you do to one side of the equation you have to do to the other

- freckles

x+1=y
subtract 1 on both sides
(x+1)-1=y-1
x+1-1=y-1
x=y-1

- anonymous

ohh ok

- freckles

\[\cot^2(x)+1=\csc^2(x) \\ \text{ subtract 1 on both sides here }\]

- anonymous

cot^2(X)=CSC^2(X)-1

- freckles

right
\[\cot^2(x)+\csc^2(x) \text{ was your left hand side } \\ \text{ replace} \cot^2(x) \text{ with } \csc^2(x)-1\]

- freckles

\[(\csc^2(x)-1)+\csc^2(x) \\ \text{ you can drop ( ) } \\ \csc^2(x)-1+\csc^2(x)\]
do you think you can finish here:

- freckles

you know how to combine like terms right?

- anonymous

no

- freckles

examples of combining like terms:
5+5=2(5)=10
a+a=2a
x^2+x^2=2x^2
log(x)+log(x)=2log(x)
sin(x)+sin(x)=2sin(x)
sin^2(x)+sin^2(x)=2sin^2(x)
sin^2(x)+4sin^2(x)=5sin^2(x)
can you find this:
csc^2(x)+csc^2(x)=?

- freckles

or not find but simplify

- anonymous

(2*x)*csc^2

- freckles

what happen to csc^2 's angle part?

- anonymous

??

- freckles

csc^2 has no meaning
csc^2(x) has meaning

- freckles

something has to be plugged into the csc^2 function to actually have meaning
csc^2 alone means nothing

- anonymous

so (2*x)*csc^2(X)

- freckles

so I think you meant to write 2csc^2(x)
this does not mean csc^2 times x
it means csc^2 of x
like means x is being plugged into the csc^2( ) function

- freckles

where does the extra x come from

- freckles

\[\csc^2(x)+\csc^2(x)=2 \csc^2(x) \]

- anonymous

ohh i see what you mena venr mind that last statment lol

- freckles

anyways do you have any questions on this one before I take off for a bit

- anonymous

id thnx alot

- freckles

np

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