anonymous
  • anonymous
WHAT IS UP WITH PROBABILITY MAN
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
1 Attachment
Republican31
  • Republican31
Looks like some sort of a bug in the school's system. This happens a lot in Aventa or Accelerate classes. Screenshot and email your teacher or mentor, if you have them.
anonymous
  • anonymous
I need help

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Republican31
  • Republican31
I'm just a 9th grader, but I don't think it makes sense at all and is a mistake. What school system is that?
anonymous
  • anonymous
What's the probability that Gary's name will be drawn on the first draw?
nincompoop
  • nincompoop
let us make this simple
nincompoop
  • nincompoop
it starts by learning from the very basic
nincompoop
  • nincompoop
if I had a coin with head and tail and I flipped it, what is the chance that it will land with its tail up?
anonymous
  • anonymous
50/50
nincompoop
  • nincompoop
what does that mean?
nincompoop
  • nincompoop
50/50 = 1
nincompoop
  • nincompoop
okay then let us make it this way
nincompoop
  • nincompoop
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mathstudent55
  • mathstudent55
When people say 50,50 they means there is a 50% chance of one event happening and 50% chance of the other event happening.
nincompoop
  • nincompoop
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nincompoop
  • nincompoop
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nincompoop
  • nincompoop
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anonymous
  • anonymous
He had 10 out of 50 percent chance each time they drew the tickets.
nincompoop
  • nincompoop
do you get this simple example @Starr_DynastyT
nincompoop
  • nincompoop
hello
anonymous
  • anonymous
just a bit
anonymous
  • anonymous
1/5 times 1/5 equals .04 or 4%. You multiply the number by itself each time you draw again without taking out the tickets.
anonymous
  • anonymous
By taking out tickets I mean taking them out without putting them back in.
anonymous
  • anonymous
I'm getting 4
mathstudent55
  • mathstudent55
The probability of an event happening is: \(p(even) = \dfrac{number ~of~desired~outcomes}{total~number~of~outcomes} \) There are 10 tickets that belong to Gary. There are a total of 50 tickets. Any ticket that belongs to Gary is a desired outcome. The number of desired outcomes is 10. There are 50 possible outcomes since there are a total of 50 tickets. For the first drawing, the probability of taking out a ticket with Gary's name is: \(p(drawing~ticket~with~Garry's ~name) = \dfrac{10}{50} = \dfrac{1}{5} \) Then the ticket is placed back in the bag, and a new drawing takes place. Since all tickets are in the bag, the second drawing is exactly the same as the first drawing, so we have: \(p(drawing~ticket~with~Garry's ~name) = \dfrac{10}{50} = \dfrac{1}{5} \) The probability of drawing Gary's name two times in a row is the product of the individual probabilities: \(p(drawing~Gary's~name ~followed ~by ~drawing~Gary's ~name) = \dfrac{1}{5} \times \dfrac{1}{5} = \dfrac{1}{25}\) Now we need to covert 1/25 to a percent. First, we convert 1/25 to a decimal by dividing 1 by 25. 1/25 = 0.04 We get 0.04 Then to convert a decimal to a percent, we multiply by 100 (move the decimal point two place to the right) 0.04 + 100 = 4 Answer is 4%

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