Will medal and fan Circle P is tangent to the x-axis and the y-axis. If the coordinates of the center are (r, r), find the length of the chord whose endpoints are the points of tangency. 2r r² r√2

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Will medal and fan Circle P is tangent to the x-axis and the y-axis. If the coordinates of the center are (r, r), find the length of the chord whose endpoints are the points of tangency. 2r r² r√2

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

1 Attachment
Find the coordinates of the other endpoint if the midpoint is M(8, 2) and the other endpoint is P(5, 6). (6.5, 4) (21, 10) (11, -2)
|dw:1439227683307:dw| Use Pythagorean Theorem to find length of chord AB

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

i dont know how..
Triangle AOB is a right triangle. The lengths of the sides are related byt the Pythagorean Theorem. If a right triangle has legs of lengths a and b, and a hypotenuse of length c, these lengths are related by\[a^2 + b^2 = c^2\]Have you seen this before?
no...
May I ask what grade you're in and what course you're working on?
im in 11 and in geometry but im doing online math this summer....
OK. You know what a right triangle is, right?
yes.
Can you identify which sides are the legs and which side is the hypotenuse?
i think so
OK. In the figure I drew, which side is the hypotenuse?
AB?
That's right.
So the other two sides are the legs. Both of these legs are \(r\) unit in length. Do you see where that comes from?
ya
Good.
The Pythagorean Theorem says that the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the legs. In our diagram\[\left( AB \right)^2 = \left( AO \right)^2 + \left( OB \right)^2\]Do you understand so far?
no u lost me
\(AB^2\) is the length of the hypotenuse squared. OK?
ok
\(AO^2\) is the length of one of the legs squared. \(OB^2\) is the length of the other leg squared. OK?
ok
Is there an easier way of learning this?
Now, for any right triangle, the lengths of the sides are related, no matter the size. The relationship is, as stated earlier\[\left( AB \right)^2 = \left( AO \right)^2 + \left( OB \right)^2\]Now, we know that the lengths of the legs (AO & OB) are equal to \(r\). So, substituting that value in, we get\[\left( AB \right)^2 = r^2 + r^2 = 2r^2\]Understand?
no not really.. Im really slow with math.. ive never been any good
If \[\left( AO \right) = r\]then \[\left( AO \right)^2 = r^2\]OK?
ok
And if \[\left( OB \right) =r\]then\[\left( OB \right)^2 = r^2\]Then by adding them together\[\left( AB \right)^2 + \left( OB \right)^2 = r^2 + r^2\]Still with me?
um kinda
Well if \[AO^2 = r^2\] and \[OB^2 = r^2\]then \[AO^2 + OB^2 = r^2 + r^2\]
okay
Now \[r^2 + r^2 = 2r^2\]You OK with that?
yas
Alright. Putting all of that together, we have\[AB^2 = AO^2 + OB^2\]\[AB^2 = r^2 + r^2\]\[AB^2 = 2r^2\]Now the question requires that we solve for AB. To do that, you need to take the square root of both sides. Can you do that?
i dont think so
What is the square root of AB^2?
umm.. No clue. Im going into all this blind
What is the square root of any number squared? If 2^2 = 4, what is the square root of 4?
2??
Right. And if 3^2 = 9, the square root of 9 is 3. So the square root of any number squared is that number. Now just do it with a variable instead of a number. So what is the square root of AB^2?
ohhh okay
So\[AB^2 = 2r^2\]\[\sqrt{AB^2} = \sqrt{2r^2}\]\[AB = \sqrt{2} \sqrt{r^2}\]And what is the square root of r^2?
umm i have no clue
We just covered it. The square root of any number squared is that same number. So the square root of r^2 is r. So your answer is\[AB = r \sqrt{2}\]
ohhh okay thank u soo much
You're welcome.
thats what i had too!!!!

Not the answer you are looking for?

Search for more explanations.

Ask your own question