A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

Verify the identity. Show your work. 1 + sec2xsin2x = sec2x the answer is 2

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Teacher:Substitute for the sec^2x on the RHS only. This is a reciprocal function. You should be able to take this from here. Me: wtf?

  2. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @thomaster

  3. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Etrainx

  4. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Zale101

  5. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I think somebody already answered this oooover here http://openstudy.com/study#/updates/509f00d7e4b013fc35a19250

  6. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i used that one but my teacher said that up there so im confuzled

  7. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @mukushla

  8. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @zepdrix

  9. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @poopsiedoodle

  10. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @mathstudent55

  11. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @TheSmartOne

  12. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Vocaloid

  13. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Vocaloid can you give me some understanding of my teachers words plz

  14. Vocaloid
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    sec^2(x) = 1/(cos^2(x))

  15. Vocaloid
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    that's basically what she's saying, substitute 1/(cos^2(x)) for sec^2(x) on the right side

  16. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1439233166138:dw|

  17. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    this is to confusing this is why i hate math lol

  18. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    That's why I'm helping you. :D

  19. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Do you know how to multiply this?

  20. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    true that thnx alot lol

  21. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i really dont

  22. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    For instance, what is \(4\times \frac{ 1 }{ 3}=?\) You only need to put 4 in the numerator. So you'll get \(\frac{ 4 }{ 3 }\).

  23. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Now, what is \( 1 + (\frac{ 1 }{ \cos^2x }\times \sin^2x)\)?

  24. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    hold on ups is at my gate

  25. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    imma go see what it is

  26. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    imm home alone so i have to get it smh lazy people deez days i leave my gate open for a reason haha

  27. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @mathway im back now

  28. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    then answer my question now

  29. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    frac(cos^2(x))

  30. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    is that right @mathway

  31. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ??

  32. misty1212
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    HI!!

  33. misty1212
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    it is clear that \[\frac{\sin(x)}{\cos(x)}=\tan(x)\]?

  34. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    hiii

  35. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  36. misty1212
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    and also it is clear that \[\sec(x)=\frac{1}{\cos(x)}\]right?

  37. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yess

  38. misty1212
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    that means \[\sec^2(x)\sin^2(x)=\frac{\sin^2(x)}{\cos^2(x)}=\tan^2(x)\]

  39. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok

  40. misty1212
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    so you are looking at \[1+\tan^2(x)=\sec^2(x)\] which is definitely true, we can get it in one step

  41. misty1212
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    start with the mother of all trig identities \[\cos^2(x)+\sin^2(x)=1\] divide both sides by \(\cos^2(x)\) and you get \[\frac{\cos^2(x)}{\cos^2(x)}+\frac{\sin^2(x)}{\cos^2(x)}=\frac{1}{\cos^2(x)}\] or \[1+\tan^2(x)=\sec^2(x)\] as needed

  42. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    woow thats alot to take in lol but it makes since

  43. misty1212
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\color\magenta\heartsuit\]

  44. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.