anonymous
  • anonymous
Verify the identity. Show your work. 1 + sec2xsin2x = sec2x the answer is 2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Teacher:Substitute for the sec^2x on the RHS only. This is a reciprocal function. You should be able to take this from here. Me: wtf?
anonymous
  • anonymous
@thomaster
anonymous
  • anonymous
@Etrainx

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anonymous
  • anonymous
@Zale101
anonymous
  • anonymous
I think somebody already answered this oooover here http://openstudy.com/study#/updates/509f00d7e4b013fc35a19250
anonymous
  • anonymous
i used that one but my teacher said that up there so im confuzled
anonymous
  • anonymous
@mukushla
anonymous
  • anonymous
@zepdrix
anonymous
  • anonymous
@poopsiedoodle
anonymous
  • anonymous
@mathstudent55
anonymous
  • anonymous
@TheSmartOne
anonymous
  • anonymous
@Vocaloid
anonymous
  • anonymous
@Vocaloid can you give me some understanding of my teachers words plz
Vocaloid
  • Vocaloid
sec^2(x) = 1/(cos^2(x))
Vocaloid
  • Vocaloid
that's basically what she's saying, substitute 1/(cos^2(x)) for sec^2(x) on the right side
anonymous
  • anonymous
|dw:1439233166138:dw|
anonymous
  • anonymous
this is to confusing this is why i hate math lol
anonymous
  • anonymous
That's why I'm helping you. :D
anonymous
  • anonymous
Do you know how to multiply this?
anonymous
  • anonymous
true that thnx alot lol
anonymous
  • anonymous
i really dont
anonymous
  • anonymous
For instance, what is \(4\times \frac{ 1 }{ 3}=?\) You only need to put 4 in the numerator. So you'll get \(\frac{ 4 }{ 3 }\).
anonymous
  • anonymous
Now, what is \( 1 + (\frac{ 1 }{ \cos^2x }\times \sin^2x)\)?
anonymous
  • anonymous
hold on ups is at my gate
anonymous
  • anonymous
imma go see what it is
anonymous
  • anonymous
imm home alone so i have to get it smh lazy people deez days i leave my gate open for a reason haha
anonymous
  • anonymous
@mathway im back now
anonymous
  • anonymous
then answer my question now
anonymous
  • anonymous
frac(cos^2(x))
anonymous
  • anonymous
is that right @mathway
anonymous
  • anonymous
??
misty1212
  • misty1212
HI!!
misty1212
  • misty1212
it is clear that \[\frac{\sin(x)}{\cos(x)}=\tan(x)\]?
anonymous
  • anonymous
hiii
anonymous
  • anonymous
yes
misty1212
  • misty1212
and also it is clear that \[\sec(x)=\frac{1}{\cos(x)}\]right?
anonymous
  • anonymous
yess
misty1212
  • misty1212
that means \[\sec^2(x)\sin^2(x)=\frac{\sin^2(x)}{\cos^2(x)}=\tan^2(x)\]
anonymous
  • anonymous
ok
misty1212
  • misty1212
so you are looking at \[1+\tan^2(x)=\sec^2(x)\] which is definitely true, we can get it in one step
misty1212
  • misty1212
start with the mother of all trig identities \[\cos^2(x)+\sin^2(x)=1\] divide both sides by \(\cos^2(x)\) and you get \[\frac{\cos^2(x)}{\cos^2(x)}+\frac{\sin^2(x)}{\cos^2(x)}=\frac{1}{\cos^2(x)}\] or \[1+\tan^2(x)=\sec^2(x)\] as needed
anonymous
  • anonymous
woow thats alot to take in lol but it makes since
misty1212
  • misty1212
\[\color\magenta\heartsuit\]

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