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anonymous
 one year ago
Verify the identity. Show your work.
1 + sec2xsin2x = sec2x
the answer is 2
anonymous
 one year ago
Verify the identity. Show your work. 1 + sec2xsin2x = sec2x the answer is 2

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Teacher:Substitute for the sec^2x on the RHS only. This is a reciprocal function. You should be able to take this from here. Me: wtf?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think somebody already answered this oooover here http://openstudy.com/study#/updates/509f00d7e4b013fc35a19250

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i used that one but my teacher said that up there so im confuzled

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Vocaloid can you give me some understanding of my teachers words plz

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.0sec^2(x) = 1/(cos^2(x))

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.0that's basically what she's saying, substitute 1/(cos^2(x)) for sec^2(x) on the right side

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439233166138:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is to confusing this is why i hate math lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That's why I'm helping you. :D

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you know how to multiply this?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0true that thnx alot lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For instance, what is \(4\times \frac{ 1 }{ 3}=?\) You only need to put 4 in the numerator. So you'll get \(\frac{ 4 }{ 3 }\).

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Now, what is \( 1 + (\frac{ 1 }{ \cos^2x }\times \sin^2x)\)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hold on ups is at my gate

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0imma go see what it is

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0imm home alone so i have to get it smh lazy people deez days i leave my gate open for a reason haha

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@mathway im back now

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then answer my question now

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is that right @mathway

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1it is clear that \[\frac{\sin(x)}{\cos(x)}=\tan(x)\]?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1and also it is clear that \[\sec(x)=\frac{1}{\cos(x)}\]right?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1that means \[\sec^2(x)\sin^2(x)=\frac{\sin^2(x)}{\cos^2(x)}=\tan^2(x)\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1so you are looking at \[1+\tan^2(x)=\sec^2(x)\] which is definitely true, we can get it in one step

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1start with the mother of all trig identities \[\cos^2(x)+\sin^2(x)=1\] divide both sides by \(\cos^2(x)\) and you get \[\frac{\cos^2(x)}{\cos^2(x)}+\frac{\sin^2(x)}{\cos^2(x)}=\frac{1}{\cos^2(x)}\] or \[1+\tan^2(x)=\sec^2(x)\] as needed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0woow thats alot to take in lol but it makes since

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[\color\magenta\heartsuit\]
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