help plz medal and fan Simplify sin^2 theta /1- cos^2 theta

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help plz medal and fan Simplify sin^2 theta /1- cos^2 theta

Mathematics
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\[\huge\rm cos^2 \theta + \sin^2 \theta =1 \]you should remember this equation!!
solve for sin^2theta
-cos(2 theta) 2 sin^2(theta)-1

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Other answers:

cos^2 theta .. yes ????
what about it ? :=)
is that the answer ????
no
Okay let me try and get it
sure!
sin^2theta +cos^2theta = 1 1-cos^2theta=sin^2theta so we can write -> sin^2theta/sin^2theta = 1 but the condition is that sin(theta) does not equal 0
sin2theta
Yes ??
that's one of the option....
can u explain how did u get sin2theta
By 1-cos2theta=sin2theta........................... i think
\[\frac{ \sin^2\theta }{\color{ReD}{ 1-\cos^2 }}\] now replace 1-cos^2for sin^2x bec 1-cos^2x=sin^2x
Omg i dont understand
\[\huge\rm cos^2 \theta + \sin^2 \theta =1 \] solve for sin^2\[\rm sin^2\theta=1-\cos^2\theta\] you will get sin^2 =1-cos^2 right ?
Yes
okay so if sin^2theta =1-cos^2 you can replace the (1-cos^2) which is at the dneominator with sin^2 theta right ?
\[\huge\rm \frac{ \sin^2\theta }{\color{ReD}{ 1-\cos^2 }}\] replace 1-cos^2for sin^2x bec \[\huge\rm \color{reD}{ 1-\cos^2x}=\sin^2x \]
so the answer is sin right
\[\frac{ \sin^2 x }{ \color{reD}{\sin^2x}}=?\]
let sin^2x = a so a/a = ??
a divide by a = ??
0
no never!
there is always invisible one!!
2/2 = ??
1 lol
ye.-.
okay thnks

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